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3 years ago

Which Quaker belief do you think influenced William Penn’s attitude toward Native Americans? Explain your answer.

Mathematics

1 answer:

Lapatulllka [165]3 years ago

8 0

Answer:

Penn and other Quakers believed that everyone had to seek God in his or her own way. Penn also thought that religious tolerance – or “liberty of conscience” – would create stronger governments and wealthier societies. Other English thinkers in the 1600s shared these ideas. But Penn had the opportunity to act on his beliefs. In Pennsylvania, religious tolerance was the law.

Penn welcomed settlers from all faiths to Pennsylvania. Each of the other American colonies had established an official church, but Penn did not. He sought out religious groups suffering in Europe, and invited them to his colony. He even gave some groups land. Yet religious tolerance did not mean that colonists of all faiths had equal rights. Only Christians could vote or hold political office. But all settlers could take part in the social and economic life of Pennsylvania.

Penn’s belief that “Religion and Policy…are two distinct things, have two different ends, and may be fully prosecuted without respect on to the other” took hold and became one of America’s most important ideals.

I hope this is enough or u can get ur answer out of it :)

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Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ

-Dominant- [34]

Answer:

$\tan(\beta)$

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something. If you have options that you're building toward, aim toward one of them.

${\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}$ and ${\sec(\theta)}={\dfrac{1}{\cos(\theta)}$

Recall the following reciprocal identity:

$\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}$

So, the original expression can be written in terms of only sines and cosines:

$\sin(\beta)\tan(\beta)\sec(\beta)\cot(\beta)$

$\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }$

$\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}$

$\sin(\beta) *\dfrac{1 }{\cos(\beta) }$

$\dfrac{\sin(\beta)}{\cos(\beta) }$

Working toward one of the answers provided, this is the tangent function.

The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero. However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to $\tan(\beta)$ .

8 0

2 years ago

Theresa is 14 years younger than her brother. Together, their total age in years is 35.

solniwko [45]

Let :
T = Theresa age
H = her brother
We know :
T = H - 14
T + H = 35
Substitute T
H -14 + H = 35
2H - 14 = 35
2H = 49
H = 49/2 = 24.5
Since we know H = 24.5 we then can substitute it to either equation.
T = H - 14
T = 24.5 - 14
T = 10.5
Theresa is 10.5 years old
Her brother is 24.5 years old

4 0

3 years ago

A mirror is in the shape of an isosceles right triangle and has a hypotenuse length of seven times the square root of two. What

frez [133]

The length of one of the legs of an isosceles right triangle and has a hypotenuse length of seven times the square root of two is 7 units.

<h3>What is an Isosceles triangle?</h3>

Isosceles triangles are triangles that has two of it sides equal to each other. The base angles of an isosceles triangle are equal.

The isosceles triangle is also a right angle triangle. The hypotenuse is the longest side of a right angle triangle.

Therefore,

hypotenuse = 7(√2)

let the length of the other legs = x

Therefore, using Pythagoras theorem

c² = a² + b²

(7(√2))² = x² + x²

49 × 2 = 2x²

98 = 2x²

x² = 98 / 2

x = √49

x = 7 units

learn more on isosceles triangle here: brainly.com/question/10412877

4 0

2 years ago

How do you solve this equation?

Travka [436]

Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1

5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4

second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1

first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3

7 0

3 years ago

Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.

Alecsey [184]

Answer:

y^2 = 28x

Step-by-step explanation:

Since the directrix is horizontal, use the equation of a parabola that opens left or right.

(y−k)^2 = 4p(x−h)

Find the vertex.

(0,0)

Find the distance from the focus to the vertex.

p = 7

Substitute in the known values for the variables into the equation

(y−k)^2 = 4p(x−h).

(y−0)^2 = 4(7)(x−0)

Simplify.

y^2 = 28x

7 0

3 years ago

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