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Tju [1.3M]
3 years ago
7

How many times does 6 go into 24?

Mathematics
2 answers:
givi [52]3 years ago
8 0

Answer:

4

Step-by-step explanation:

A good way to think of division is repeated subtraction. So we could rephrase this question as, "How many times can we take away 6 from 24". If we do this out we get:

24 - 6 - 6 - 6 - 6

24 - 24 = 0

This means we can "take" 6 four times from 24 before we have nothing left.

Or you could simply divide 24/6 to get 4!

Hope this helps

Sunny_sXe [5.5K]3 years ago
4 0

Answer:

4

Step-by-step explanation:

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What is the mode for the data set 67,73,78,71,80,74,79,76,75,70,72,​
dusya [7]

Answer:

There is no mode.

Step-by-step explanation:

Mode is a number that appears in a data set multiple times and their are no two numbers here.

3 0
2 years ago
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Which graph represents an odd function?
Nookie1986 [14]

Answer:

<h2>The first graph in the second image is an odd function.</h2>

Step-by-step explanation:

An odd function has a graph that it's symmetric about the origin, that is, the origin is like a mirror. In other words, the graph of an odd function has a specific symmetry about the origin.

So, we have to look for those graph that has symmetrical points in opposite quadrants, I and III or II and IV.

You can observe that the first graph of the second image has this behaviour. You can see that the points are symmetrical across the origin. If you graph a line defined as y=-x, you will observe that such line acts like a mirror.

Therefore, the odd function is the first graph in the second image.

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−3x + y = 4,<br><br> −9x + 5y = −1<br> find x and y
katrin [286]

Answer:

9x - 3y = -12

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2y = -13

y = -13/2

-3x - 13/2 = 8/2

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x = -21/6 = -7/2

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3 0
3 years ago
Is this a function? PLEASE THIS IS URGENT!!!!
trapecia [35]

Answer:

<h2>NO</h2>

Step-by-step explanation:

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6 0
3 years ago
ASAP someone please simply two exponents
zhannawk [14.2K]

Answer:

1.) m^{15}

2.) =\frac{1}{y^{15}}

Give me a comment if you want the explanation.

1.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(m^3\right)^5=m^{3\cdot \:5}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15

=m^{15}

2.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(y^{-3}\right)^5=y^{-3\cdot \:5}

=y^{-3\cdot \:5}

=y^{-15}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\frac{1}{y^{15}}

4 0
3 years ago
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