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3 years ago

Please help me I really need help

Mathematics

2 answers:

elixir [45]3 years ago

8 0

Answer:

Step-by-step explanation:

Lowest Common Multiple= 56

IgorLugansk [536]3 years ago

4 0

Answer:

56 seconds

Step-by-step explanation:

One way of doing this is to write out sequences for the number of seconds that elapse in each case.

First bulb: 0 7 14 28 56 63

Second bulb: 0 8 16 24 32 40 48 56

Both bulbs flicker after 56 seconds.

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17 times 14 times 123

LUCKY_DIMON [66]

Answer:

29274

Step-by-step explanation:

Because 17*14=238 and 238*123=29274

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3 years ago

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balandron [24]

Answer:

Step-by-step explanation:

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5 0

3 years ago

My Question: Q=1/2P+15, for P

Mekhanik [1.2K]

P=2(9-15) is what i got first i simplify 1/2p to p/2, then subtract from both sides, multply both sides by 2, then regroup terms, and last switch sides

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3 years ago

Lin uses an app to graph the charge on her phone.

exis [7]

Answer:

See below

Step-by-step explanation:

<u>Use the graph to answer the following questions:</u>

When did she start using her phone?

At 2 afternoon

When did she start charging her phone?

At 8 afternoon

While she was using her phone, at what rate was Lin’s phone battery dying?

<u>From 100% to 40% between 2PM and 4 PM:</u>

(100 - 40)/(4 - 2) = 60/2 = 30% per hour

8 0

2 years ago

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A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0

2 years ago