The value is 5 tens because the 5 is in the tens place
Answer:
Kite
Step-by-step explanation:
To graph quadrilateral with points:
A(-1,-2)
B(5,1)
C(-3,1)
D(-1,4)
Thus, we graph the the given points and join the corners. The quadrilateral formed has the following features:
Measure of segment AB= Measure of segment BD = 6.708 units
Measure of segment AC= Measure of segment CD = 3.605 units
Thus, adjacent pair of sides of the quadrilateral are congruent.
Major diagonal BC cuts the minor diagonal AD at point E such that:
Measure of segment AE= Measure of segment ED = 3 units
m∠AEB = m∠DEB = 90°
Thus, major diagonal is a perpendicular bisector of the minor diagonal.
The above stated features fulfills the criterion of a kite.
Hence, the given quadrilateral ABCD is a kite.
Well I'm assuming that you want me to simplify the fraction 40/6. Since 40 can go into 6 multiple times, this fraction is going to be a mixed number.
40/6 in simplest form is 6 2/3. Hope I helped!
Step-by-step explanation:
With reference to the regular hexagon, from the image above we can see that it is formed by six triangles whose sides are two circle's radii and the hexagon's side. The angle of each of these triangles' vertex that is in the circle center is equal to 360∘6=60∘ and so must be the two other angles formed with the triangle's base to each one of the radii: so these triangles are equilateral.
The apothem divides equally each one of the equilateral triangles in two right triangles whose sides are circle's radius, apothem and half of the hexagon's side. Since the apothem forms a right angle with the hexagon's side and since the hexagon's side forms 60∘ with a circle's radius with an endpoint in common with the hexagon's side, we can determine the side in this fashion:
tan60∘=opposed cathetusadjacent cathetus => √3=Apothemside2 => side=(2√3)Apothem
As already mentioned the area of the regular hexagon is formed by the area of 6 equilateral triangles (for each of these triangle's the base is a hexagon's side and the apothem functions as height) or:
Shexagon=6⋅S△=6(base)(height)2=3(2√3)Apothem⋅Apothem=(6√3)(Apothem)2
=> Shexagon=6×62√3=216
