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goldenfox [79]
4 years ago
9

How to find sin A, sin (90°-A), and tan A?

Mathematics
1 answer:
finlep [7]4 years ago
6 0

1) sin(90 - A) = cos A=√(2/3) or √6/3

2) sin²A + cos²A=1

sin²A= 1 -cos²A=1 - (√2/3)²= 1 - 2/3= 1/3

sin A = 1/√3 or √3/3

3) tan A= sin A/ cos A= (1/√3)/(√2/√3)= 1/√2

tan A = 1/√2 or √2/2

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vladimir1956 [14]

Answer:

A. 6

Step-by-step explanation:

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Whats the inequality of the product of a number n and 2 is no less than 14
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Product = Multiply
No less = \geq
So, we need to use this info.
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5 0
3 years ago
Trigonometry
xxTIMURxx [149]

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9 units

Step-by-step explanation:

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I need help with math homework
kobusy [5.1K]

Answer:

A. (0, 1) and (2, -2)

B. Slope (m) = -³/2

C. y + 2 = -³/2(x - 2)

D. y = -\frac{3}{2}x + 1

E. \frac{3}{2}x + y = 1

Step-by-step explanation:

A. Two points on the line from the graph are: (0, 1) and (2, -2)

B. The slope can be calculated using two points, (0, 1) and (2, -2):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - 1}{2 - 0} = \frac{-3}{2} = -\frac{3}{2}

Slope (m) = -³/2

C. Equation in point-slope form is represented as y - b = m(x - a). Where,

(a, b) = any point on the graph.

m = slope.

Substitute (a, b) = (2, -2), and m = -³/2 into the point-slope equation, y - b = m(x - a).

Thus:

y - (-2) = -³/2(x - 2)

y + 2 = -³/2(x - 2)

D. Equation in slope-intercept form, can be written as y = mx + b.

Thus, using the equation in (C), rewrite to get the equation in slope-intercept form.

y + 2 = -³/2(x - 2)

2(y + 2) = -3(x - 2)

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y = -\frac{3}{2}x + 1

E. Convert the equation in (D) to standard form:

y = -\frac{3}{2}x + 1

\frac{3}{2}x + y = 1

8 0
3 years ago
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