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3 years ago

How to find sin A, sin (90°-A), and tan A?

Mathematics

1 answer:

finlep [7]3 years ago

6 0

1) sin(90 - A) = cos A=√(2/3) or √6/3

2) sin²A + cos²A=1

sin²A= 1 -cos²A=1 - (√2/3)²= 1 - 2/3= 1/3

sin A = 1/√3 or √3/3

3) tan A= sin A/ cos A= (1/√3)/(√2/√3)= 1/√2

tan A = 1/√2 or √2/2

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Use integration by parts to find the integrals in Exercise. ∫(4x-12)e-8x dx.

stepladder [879]

Answer:

$e(2x^{2} -12x)-4x^{2}+C$

Step-by-step explanation:

We have been given an indefinite integral as $\int \left(4x-12\right)e-8x\:dx$ . We are asked to find the given integral.

Let us solve our given problem.

$\int \left(4x-12\right)e\:dx-\int 8x\:dx$

Take out constant:

$e\int \left(4x-12\right)\:dx-8\int x\:dx$

$e(\int 4x\:dx -\int 12\right\:dx)-8\int x\:dx$

$e(\frac{4x^{1+1}}{2} -12x)-8*\frac{x^{1+1}}{1+1}+C$

$e(\frac{4x^{2}}{2} -12x)-8*\frac{x^{2}}{2}+C$

$e(2x^{2} -12x)-4x^{2}+C$

Therefore, our required integral would be $e(2x^{2} -12x)-4x^{2}+C$ .

5 0

3 years ago

I NEED HELP!!!!!!!!!!!!!!!!!!

ratelena [41]

Answer:

thats easy

Step-by-step explanation:

but thanks 4 the points

4 0

2 years ago

How do I solve this math problem? M — = -3 4

harina [27]

-12

Step-by-step explanation:

We know 12 divided by 4 is 3 so the same is so in the negatives

6 0

3 years ago

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The area of a triangle is 11.5 square in the base is 23 in what is the height in inches

coldgirl [10]

Answer:

Height = 1 inch

Step-by-step explanation:

area of triangle = 1/2 x base x height

11.5 =1/2 x 23 x height

23/23 = height

height = 1

6 0

3 years ago

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A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

3 years ago