4 years ago

How to find sin A, sin (90°-A), and tan A?

Mathematics

1 answer:

finlep [7]4 years ago

6 0

1) sin(90 - A) = cos A=√(2/3) or √6/3

2) sin²A + cos²A=1

sin²A= 1 -cos²A=1 - (√2/3)²= 1 - 2/3= 1/3

sin A = 1/√3 or √3/3

3) tan A= sin A/ cos A= (1/√3)/(√2/√3)= 1/√2

tan A = 1/√2 or √2/2

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