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kondor19780726 [428]
2 years ago
13

What is the slope that passes through the points (5, -11) and (-9, 17)?

Mathematics
1 answer:
Umnica [9.8K]2 years ago
8 0
The coreect point is (4,7)
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Guys plz help me answer this!!!!
Zolol [24]

Answer:

p= 2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

6 0
3 years ago
I need help in this question
tiny-mole [99]

Answer:

C. 12/15

Step-by-step explanation:

2/3, 6/9, and 18/27 all simplify to 2/3. 12/15 does not.

8 0
2 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
2 years ago
HELP ME A.S.A.P. PLZZZZ
Ronch [10]

Answer:

A = 66.5 in²

Step-by-step explanation:

There are a few different equations to find the area of a rhombus.  If you are given the measurements of the two diagonals, you can use the following formula:  

Area (A) = \frac{d_{1}d_{2} }{2}

Using this formula, you can multiply the measures of the diagonals and then divide by 2:

area = \frac{(9.5)(14)}{2} =\frac{133}{2}=66.5in^{2}

7 0
3 years ago
Please help i'm desperate!!
Leya [2.2K]
I’m not sure maybe if there was an imagine I’d be able to answer this question.
6 0
2 years ago
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