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3 years ago

If a single fair die is rolled, find the conditional probability of rolling a 4 given that the number rolled is less than 3

1 answer:

7 0

Given that the number rolled is less than 3,
we know that it must be either a 1 or a 2 .

The probability of it being a 4 is zero.

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In Ms Barclay's classroom 2/5 students play chess. 5/6 of the students play Sudoku. If there are 30 students, in her class how m

Nonamiya [84]

Answer:

12 students play chess

and 25 students play Sudoku

Step-by-step explanation:

There are 30 students in Ms Barclay's classroom.

2/5 students play chess.

i.e. $\dfrac{2}{5}\times 30$ play chess

i.e. 12 students play chess

5/6 of the students play Sudoku.

i.e. $\dfrac{5}{6}\times 30$ play Sudoku

i.e. 25 students play Sudoku

Hence, 12 students play chess

and 25 students play Sudoku

6 0

3 years ago

To get a b in math, alexandria pappas must average 80 on five tests. scores on the first four tests were 8484, 7575, 8181, a

Grace [21]

Answer: 84

Explanation:

Total for 5 tests = 80 x 5 = 400

Total for 4 tests = 84 + 75 + 81 + 76 = 316

5th score = 400 - 316 = 84

5 0

3 years ago

What is the answer to this?

Alisiya [41]

Answer:

i think it was -(1/3)

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

I need help with number 10

borishaifa [10]

Answer:

Step-by-step explanation:

it should be a triangle that has less the 90 degree corners and all sides are an equal length

7 0

3 years ago

PLEASE PLEASE HELP ME OUT ITS URGENT What are the solutions to the quadratic equation?

mixer [17]

Answer: Choice C) $x = 4\pm2\sqrt{10}$

This is the same as saying $x = 4+2\sqrt{10} \ \ \text{ or } \ \ x = 4-2\sqrt{10}$

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Explanation:

First get everything to one side

x^2 + 13 = 8x + 37

x^2 + 13 - 8x - 37 = 0

x^2 - 8x - 24 = 0

Here we have a quadratic in the form ax^2+bx+c = 0

Note how a = 1, b = -8, c = -24

Those values are plugged into the quadratic formula below

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-8)\pm\sqrt{(-8)^2-4(1)(-24)}}{2(1)}\\\\x = \frac{8\pm\sqrt{160}}{2}\\\\x = \frac{8\pm\sqrt{16*10}}{2}\\\\x = \frac{8\pm\sqrt{16}*\sqrt{10}}{2}\\\\x = \frac{8\pm4*\sqrt{10}}{2}\\\\x = \frac{2(4\pm2\sqrt{10})}{2}\\\\x = 4\pm2\sqrt{10}$

This shows the answer is choice C.

The plus minus breaks down that equation these two solutions

$x = 4+2\sqrt{10} \ \ \text{ or } \ \ x = 4-2\sqrt{10}$

6 0

3 years ago

Read 2 more answers