BE is parallel to CD, therefore, m∠BEC=m∠ECD, therefore mBC=mDE
BE is the diameter, so Arc BE is 180 degree
mBC+mCD+mDE=180
replace mCD with 3mBC, and replace mDE with mBC: mBC+3mBC+mBC=180
5mBC=180
mBC=180/5=36
mCD=3mBC=3*36=108
the inscirbed angle m∠ECD= the measure of arc DE=36
<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.
We require B(n) = 0...i.e. balance of 0 after n months.
so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
Then, with some algebraic juggling we get:
n = -[log(1 - (Ai/P)]/log(1 + i)
Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43
Also, i = (13.6/100)/12 => 0.136/12 per month
i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)
so, n = 4.15 months...i.e. 4 payments + remainder
b) Now we have A = $754.43 - $300 = $454.43 so,
n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)
so, n = 1.54 months...i.e. 1 payment + remainder
</span>
Answer:
<h3>p(+)q=SQR(p^2+q^2)</h3>
8(+)6=SQR(8^2+6^2)
SQR(64+36)
SQR(100)
=10
Step-by-step explanation:
p + Q is equal to square root of p square + Q Square
sqr means square root
Step-by-step explanation:
Step 1: Plot the points
L(1,2)
M(0,-1)
J(1,-2)
K(2,-1)
Step 2: Multiply each point by 5.
and record thise points so we have
L(5,10)
M(0,-5)
J(5,-10)
K(10,-5)
Step 3: Plot those points.
5(6*3) = 5(18) = 90
(5*6)3 = (30)3 = 90
The answer is the same by the associative law.
