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Marrrta [24]
3 years ago
14

How is the value of a product determine

Business
2 answers:
puteri [66]3 years ago
8 0
It mostly accepted my the seller or the buyer im preety sure!
jasenka [17]3 years ago
3 0
<span>The market value of a product is the price point that is generally accepted by seller and buyer




Hope this helps best of luck =]
</span>
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Using the continuous compounding equation, if someone invested $5,000 at an interest rate of 3.5%, and someone else invested $5,
UNO [17]

Answer:

Therefore after 16.26 unit of time, both accounts have same balance.

The both account have $8,834.43.

Explanation:

Formula for continuous compounding :

P(t)=P_0e^{rt}

P(t)=  value after t time

P_0= Initial principal

r= rate of interest annually

t=length of time.

Given that, someone invested $5,000 at an interest 3.5% and another one  invested $5,250 at an interest 3.2% .

Let after t year the both accounts have same balance.

For the first case,

P= $5,000, r=3.5%=0.035

P(t)=5000e^{0.035t}

For the second case,

P= $5,250, r=3.5%=0.032

P(t)=5250e^{0.032t}

According to the problem,

5000e^{0.035t}=5250e^{0.032t}

\Rightarrow \frac{e^{0.035t}}{e^{0.032t}}=\frac{5250}{5000}

\Rightarrow e^{0.035t-0.032t}=\frac{21}{20}

\Rightarrow e^{0.003t}=\frac{21}{20}

Taking ln both sides

\Rightarrow lne^{0.003t}=ln(\frac{21}{20})

\Rightarrow 0.003t}=ln(\frac{21}{20})

\Rightarrow t}=\frac{ln(\frac{21}{20})}{0.003}

\Rightarrow t= 16.26

Therefore after 16.26 unit of time, both accounts have same balance.

The account balance on that time is

P(16.26)=5000e^{0.035\times 16.26}

              =$8,834.43

The both account have $8,834.43.

7 0
3 years ago
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