Answer:
a = 1565217.39 ft / s ^ 2
t = 0.001725 seconds
Step-by-step explanation:
The first thing is to use the same system of units therefore we will pass the 28 inches to feet, like this:
28 in * (1 ft / 12 in) = 2.33 ft
Now yes, we can continue, we have the following data:
vi = 0
vf = 2700 ft / s
the equations in this case are as follows:
vf = vi + a * t
vf = a * t
rearranging for a
a = vf / t (1)
now with the position equation we know that:
x = vi * t + (a * t ^ 2) / 2
x = (a * t ^ 2) / 2 (2)
now replacing (1) in (2), we are left with:
x = (vf / t) * (t ^ 2) / 2
knowing that x would be 2.33 ft, which is when the cannonball exits the cannon.
2.33 = 2700 * t / 2
t = 2.33 * 2/2700 = 0.001725 seconds.
and now replace in (1)
a = vf / t = 2700 / 0.001725 = 1565217.39 ft / s ^ 2
Step-by-step explanation:
first you have to do the subtraction in the parentheses so it's 8+3(4) and then you multiply the 3 by 4 (only the 3 because the 8 isn't next to the multiply) and then you have 12, add 8 and it's 20
when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one, from where we can use proportions to get their sides, so Check the picture below.
.5 cups is equal to 1/2 cup.
Half of 1 cup equals 4 fluid ounces.
The principal, real, root of:
![\sqrt[2]{55}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B55%7D)
=7.41619849
