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3 years ago

A circle has a radius of 17 mm. An arc length of the circle is 30 mm. What is the area of the sector that is bound by the arc

Mathematics

2 answers:

nikklg [1K]3 years ago

7 0

Answer:

255mm squared

Step-by-step explanation:

it is true i got it wrong and found out the hard way

Mama L [17]3 years ago

7 0

Answer:

255

Step-by-step explanation:

edge

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3 years ago

Charles wants to determine which car is the fastest. The actual speed of four cars is shown below: Car A B C D Speed (in km/h) 6

marysya [2.9K]

it would be car d because of what the time was on the chart (i did the test and it was correct)

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4 years ago

A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo

katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the box $V=x^2z$

Volume of the box $=12 ft^3\\$

$Therefore, x^2z=12\\z=\frac{12}{x^2}$

The material for the base costs $\$0.17/ft^2$ , the material for the sides costs $\$0.10/ft^2$ , and the material for the top costs $\$0.13/ft^2$ .

Area of the base $=x^2$

Cost of the Base $=\$0.17x^2$

Area of the sides $=4xz$

Cost of the sides= $=\$0.10(4xz)$

Area of the Top $=x^2$

Cost of the Base $=\$0.13x^2$

Total Cost, $C(x,z) =0.17x^2+0.13x^2+0.10(4xz)$

Substituting $z=\frac{12}{x^2}$

$C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}$

To minimize C(x), we solve for the derivative and obtain its critical point

$C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2$

Recall: $z=\frac{12}{x^2}=\frac{12}{2^2}=3\\$

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0

3 years ago

Simplify (b-a)U(c-a)?

exis [7]

Answer:

Step-by-step explanation:

3 0

2 years ago

I need to know the whole thing please help

aleksley [76]

Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method Frequency

Public Transport 12

Car 15

Cycle 9

Walk 16

Find the relative frequency of.

The formula used will be: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 16/52

Decimal = 0.308

c) A student not cycling to school.

We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

Size of sample space. 52

Apply formula: $Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}$

Fraction = 43/52

Decimal = 0.827

6 0

3 years ago