The answer is 0 percent.
If we represent dominant trait (wrinkled seeds) with A and recessive trait (non-wrinkled seeds) with a, then genotypes are AA (dominant homozygous), Aa (heterozygous), and aa (recessive homozygous). The phenotype of wrinkled seed is determined by genotypes either Aa or AA. Since the cross of a plant with wrinkled seed with a plant with non-wrinkled sees gives only wrinkled-seeded offspring, the plant with wrinkled seeds must be dominant heterozygous.
Let's look at both examples.
If wrinked-seeded parent contains one non-wrinkled allele, it must be heterozygous (Aa):
Parents: Aa x aa
Offspring: Aa Aa aa aa
So, the 50% of offspring has wrinkled seeds and 50% has <span>non-wrinkled seeds.
If </span><span>the wrinkled-seeded parent does not contain any non-wrinkled allele:
</span>Parents: AA x aa
Offspring: Aa<span> Aa Aa Aa
</span><span>
Thus, al</span><span>l of the offspring are heterozygous and all of them have wrinkled seeds.</span>
Glycogen is formed in the liver during the absorptive state. Glycogen formation is called glycogenesis, which takes place depending on the demand for glucose and ATP. If both are present in relatively high amounts, then the excess of insulin promotes the glucose conversion into glycogen for storage in the liver and muscle cells.
<span>carriers are not eliminated by the disease before passing the defective alleles on to their offspring</span>
I'm pretty sure it'll increase. (Not sure!!)
-Laura Benbrahim.
They fly around to find their prey because "you can catch flies with honey, but you can catch more honeys being fly".
