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Tamiku [17]
4 years ago
8

A beam of light passes from air into a cube of zirconium if the angle of incidence is 40”what is the angle of refraction ?

Physics
1 answer:
Colt1911 [192]4 years ago
5 0

Answer:

50 degrees

Explanation:

Usually in physics in solving such questions refractive index of air is taken as 1.00 (n=1.00) by assuming that air is a vacuum. Hence, the light ray passes from water to air at an angle of incident of 40 degrees, it means that it has angle of 50 degrees to the normal line.

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An electromagnet is strong enough to lift 200 kg of mass. If you double the number of turns of wire around the core and triple t
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Magnetic field is proportional to NIA.

N is the number of turns, I is the current and A is the area

You see N=2n, I = 3 i. Therefore, it will 6 times stronger

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An automobile with a mass of 1180 kg is traveling at a speed v = [06] ____________________ m/s. a. What is its kinetic energy in
iogann1982 [59]

Complete Question:

An automobile with a mass of 1180 kg is traveling at a speed v =2.51 m/s. What is its kinetic energy in SI units? What speed (m/s) must an 82.7-kg person move to have the same kinetic energy? At what speed (m/s) must is 12.1-g bullet move to have the same kinetic energy? What would be the speed (m/s) of the automobile if its kinetic energy were doubled?

Answer:

a) 3717.1 J b) 9.48 m/s c) 783.8 m/s d) 3.55 m/s

Explanation:

a)

  • By definition, the kinetic energy of a mass m with a speed v, is as follows:

      K = \frac{1}{2} * m *v^{2}

  • if m= 1180 Kg, and v= 2.51 m/s, the kinetic energy can be calculated as follows:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 1180 kg*(2.51 m/s)^{2} = 3717.1 J

b)

  • If the kinetic energy must be the same, and m= 82,7 Kg, we can write the following expression:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 82.7 kg*((v)(m/s))^{2} = 3717.1 J

  • We can solve the above equation as follows:

        v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{82.7kg} } = 9.48 m/s

c)

  • If K remains the same, and m = 12.1 g = 0.0121 kg (in SI units). we can solve for v  as follows:

       v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*3717.1J}{0.0121kg} } = 783.8 m/s

d)

  • Now, if the kinetic energy were doubled, we would have the following equation:

       K = \frac{1}{2} * m *v^{2} =  \frac{1}{2} * 1180 kg*((v) m/s)^{2} = 3717.1 J * 2 = 7434.2 J

  • We can solve for the new speed v as follows:

        v =\sqrt{\frac{2*K}{m} } = \sqrt{\frac{2*7434.2J}{1180kg} } = 3.55 m/s

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How long will it take a basketball starting from rest to roll without slipping 2.6 m down an incline that makes an angle of 30.8
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<em>t = 1.02 s</em>

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downward force along the inclined plane = F = mgsin(30.8)

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⇒                                                                      a = 9.81 sin(30.8)

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now we have

displacement = s = 2.6 m

acceleration   = a = 5.02m/s^2

initial velocity = Vi = 0m/s

time                 = t =  ?

<u>APPLYING THE 2ND EQUATION OF MOTION:</u>

<em>    S = (Vi)(t)+0.5at^2</em>

<em>2.6 = 0(t) + 0.5 * 5.02 * t^2</em>

<em>t = 1.02 s</em>

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