Answer:
The magnitude of the electric field be 171.76 N/C so that the electron misses the plate.
Explanation:
As data is incomplete here, so by seeing the complete question from the search the data is
vx_0=1.1 x 10^6
ax=0 As acceleration is zero in the horizontal axis so
Equation of motion in horizontal direction is given as


Now for the vertical distance
vy_o=0
than the equation of motion becomes

Now using this acceleration the value of electric field is calculated as

Here a is calculated above, m is the mass of electron while q is the charge of electron, substituting values in the equation

So the magnitude of the electric field be 171.76 N/C so that the electron misses the plate.
Answer:
a) 17 km
b) 9 km
Explanation:
The distance is the length of the path.
A to C: 5 km
B to C: 4 km
C to B: 4 km
B to C: 4 km
Total distance = 5 km + 4 km + 4 km + 4 km = 17 km
Displacement is the difference between the starting point and ending point.
Displacement = 9 km − 0 km = 9 km
Answer:by book 2 do you mean the original or re, if you you mean who taught kaneki to control his kagune it was yoshimura (the manager) but if your talking about how to fight with control of his kagune its was Yomo
Explanation: if I'm wrong correct me and i'll do more research
Answer:
-72\times 10^{-19}C[/tex]
Explanation:
Both electron and proton have the same amount of charge but signs are opposite , electron contains negative charge and proton contain positive charge
Charge on 1 electron = 
So charge on 206 electron 
Charge on 1 proton = 
So charge on 161 electron 
So charge of the system = 
