Ask question

Ask question

All categories

3 years ago

6

Elwin Osbourne, CIO at GFS, Inc., is studying employee use of GFS e-mail for non-business communications. He plans to use a 98%

confidence interval estimate of the proportion of e-mail messages that are non-business; he will accept a 0.05 error. Previous studies indicate that approximately 30% of employee e-mail is not business related. Elwin should sample _______ e-mail messages.

Computers and Technology

1 answer:

ziro4ka [17]3 years ago

3 0

Answer: 456

Explanation:

Given : Significance level : $\alpha= 1-0.98=0.02$

Critical value : $z_{\alpha/2}=2.33$

Margin of error : $E=\pm0.05$

The prior proportion of employee e-mail is not business related: $p=0.30$

The formula to find the sample size is given by :-

$n=(p(1-p))(\dfrac{z_{\alpha/2}}{E})^2$

i.e. $n=(0.3(0.7))(\dfrac{(2.33)}{0.05})^2=456.0276\approx456$

Hence, Elwin should sample 456 e-mail messages.

You might be interested in

Juan is a network administrator and must set up a VPN for his company's network. To allow safe communication, he should

Mekhanik [1.2K]

Answer:

select Control Panel, then Network Protocols, then Internet

4 0

3 years ago

Imagine a typical website that works as a storefront for a business, allowing customers to browse goods online, place orders, re

Gwar [14]

Answer: See explanation

Explanation:

Following the information given in the question, the testing process for the website will include testing the links that are on the site.

Another that ng to test is to check if the menus and the buttons are working properly. Furthermore, the layout should be ensured that it's consistent as well as the ease with which the website can be used.

5 0

3 years ago

Which method adds 10 to the right end of the array?<br> myArray.<br> insert<br> (10)

vladimir1956 [14]

JavaScript has a set of mutator functions that allow you to modify the contents of an array without referencing the individual elements.To add to to myArray we us the push() method

<h3>Adding Elements to an Array</h3>

To add to to myArray we us the push() method

(10)

myArray.push(10)

There are two mutator functions for adding elements to an array: push() and unshift(). The push() function adds an element to the end of an array:

var nums = [1,2,3,4,5]; print(nums); // 1,2,3,4,5 nums.push(6);

print(nums); // 1,2,3,4,5,6

var nums = [1,2,3,4,5]; print(nums); // 1,2,3,4,5 nums[nums.length] = 6; print(nums); // 1,2,3,4,5,6

Learn more about arrays here:

brainly.com/question/24275089

6 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

3 years ago

To define an additional field in Datasheet view, tap or click the ____ column heading.

Ksenya-84 [330]

The correct answer for the question that is being presented above is this one: "D) click to add." To define an additional field in Datasheet view, tap or click the<span> click to add </span>column heading.
Here are the following choice:
A) insert field
B) blank field
C) new field
D) click to add

3 0

4 years ago