Answer:
import java.util.Scanner;
import java.util.Arrays;
import java.util.Random;
public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter low: ");
int low = scan.nextInt();
System.out.print("Enter high: ");
int high = scan.nextInt();
scan.close();
int rndnumbers[] = new int[10];
Random r = new Random();
for(int i=0; i<rndnumbers.length; i++) {
rndnumbers[i] = r.nextInt(high-low+1) + low;
}
for(int i=0; i<rndnumbers.length; i++) {
System.out.printf("%d: %d\n", i, rndnumbers[i]);
}
}
}
I would say none of the above as A, B, and C do not seem like sensible answers.
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Answer:
The answer is "14".
Explanation:
Let the IP address 
When it borrowed 4 bits
If the borrowed bits are left out then:
The Number of useable host addresses:
