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IgorC [24]
3 years ago
12

At a New Year’s party, Brian’s guests drank 3 liters of club soda, 7 liters of cola, 5 liters of punch, 6 liters of fruit juice,

5 liters of seltzer, and 6 liters of ginger ale. There were 40 guests at the party. On average, how many liters of beverages did each person consume?
Mathematics
2 answers:
Vilka [71]3 years ago
7 0
3+7+5+6+5+6=32

THERE WERE 40 GUESTS

SO 40/32=1.25

ANSWER=1.25
diamong [38]3 years ago
4 0
To find the average number of liters that each person consumed, let us first find out how many liters were consumed in total. Add up all of the liters:

3 + 7 + 5 + 6 + 5 + 6 = 32 liters

There were 40 guests at the party, so in order to find out the average amount that each person consumed, we must divide the number of liters by the number of people at the party:

\frac{32}{40}= \frac{16}{20}= \frac{8}{10}= \frac{4}{5}

This means that on average, each person consumed \frac{4}{5} of a liter of beverage.
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Answer:

Step-by-step explanation:

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6 0
1 year ago
Jovita divides $12,000 into three investments: a savings account paying 4% annual interest, a bond paying 6%, and a money market
xenn [34]

Answer:

$2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

Step-by-step explanation:

Let a, b, and c be the fractions of the $12,000 that is invested in the savings, bond, & money fund respectively.

Let S1, S2, S3 be the total monies from the savings, bond, & money fund after the year with interest respectively.

We know that a+b+c=1

and

S1+S2+S3 = 12000 + 860

S1+S2+S3 = 12860

From, the question, we know that b = 2a, and c = 1 - 3a based on the condition of 2 times more in the bond account that the savings account.

Thus;

S1 = a(12000)(1.04) = 12480a

S2 = 2a(12000)(1.06) = 25,440a

S3 = (1 - 3a)(12000)(1.09) = 13080 - 39240a

We already know that;

S1+S2+S3 = 12860

Thus, Adding the 3 equations gives;

12480a + 25,440a + 13080 - 39240a = 12860

Thus, simplifying gives;

13080 - 12860 = 39240a - 12480a - 25,440a

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a = 220/1320

a = 0.1667

So,b = 2 x 0.1667 = 0.3334

c = 1 - (3 x 0.1667)

c = 1 - 0.5

c = 0.5

Thus,

S1 = 12480a = 12480 x 0.1667 ≈ $2080

S2 = 25,440a = 25440 x 0.1667 ≈ $4241

S3 = 13080 - 39240(0.1667) ≈ 6539

So, $2080 was invested in the savings account, $4241 was invested in the bond account, & $6539 was invested in the money fund.

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