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allsm [11]
3 years ago
9

Ella takes 1 3/5 hours to complete a painting. Holly takes 3/4 of the time that Ella takes. How long will Holly take to complete

5 paintings?
Mathematics
1 answer:
Misha Larkins [42]3 years ago
3 0
1. you have to figure out what 3/4 of Ella's time is.
1 \frac{3}{5}  =  \frac{8}{5}
(You find that out by multiplying 5x1. Then add 3.)
2. Convert the fractions into decimals. (This will help make it easier when dividing.)
\frac{8}{5}  = 8 \div 5 = 1.6
\frac{3}{4}  = 3 \div 4 = .75
3. Next you are going to divide 1.6 by .75
1.6 \div .75 = 2.13
4. Now multiple 2.13 by 5.
2.13 \times 5 = 10.65
Answer is 10

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FromTheMoon [43]

Answer:

1. A and L

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Step-by-step explanation:

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5 0
3 years ago
Keianaka and Christopher are participating in a volunteer project painting homes for elderly people in their neighborhood. Keian
Burka [1]
The K-team can paint a whole house in 60 minutes (super fast!!!). How much of a house can the team paint in 1 minute?  The K-team can paint 1/60 of a house per minute.

The C-team can paint a whole hose in 80 minutes. How much of a house can the team paint in 1 minute? The C-team can paint 1/80 of a house per minute.

Suppose both teams paint for the same amount of time --  call the time t (minutes).

Combine the work they do to paint 1 whole house:

\frac{1}{60}t+\frac{1}{80}t=1

Multiply all the terms by the Least Common Denominator,  LCD = 240.

240(\frac{1}{60})t+240(\frac{1}{80})t=240

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8 0
4 years ago
Suppose a student carrying a flu virus returns to an isolated college campus of 5000 students. Determine a differential equation
zloy xaker [14]

Answer:

x(t) = 5000*( 1 - e^-kt)  

Step-by-step explanation:

Given:

- Total number of students n = 5000

Find:

Differential equation governing the number of students x(t) who have contracted the flu.

Solution:

- Number of non-affected students = (5000 - x)

Hence,

- Rate at which students are infected:

                             dx / dt = k*(5000 - x )

- separate variables:

                             dx / (5000 - x ) = k*dt

- Integrate both sides:

                             - Ln(5000 - x) = kt + C

- Evaluate C for x = 0 @ t = 0

                             - Ln(5000 - 0) = k*0 + C

                               C = - Ln(5000)

- The solution to ODE is:

                               Ln(5000 - x) = -k*t + Ln(5000)

                                5000 - x = 5000*e^-kt

                                 x(t) = 5000*( 1 - e^-kt)  

                             

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Which of the following lines represents the line of best fit for the scatter plot?
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The answer should be option C.

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