Question

three consecutive odd integers are such that times the smallest is 9 more than twice the largest. Find the 3 numbers ​

Answer 1

Answer:

If we assume 'x' an odd number let's say 1, then the other two consecutive odd integers are 1+2 and 1+4,

So assume the three consecutive odd integers be x, x+2 and x+4.

It's obvious that x is the smallest and x+4 is the largest.

Therefore 3x=9+2(x+4)

Solving for x: we get x = 17.

Hence, the three consecutive odd no. are 17, 19, 21

I hope it's helpful!