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3 years ago

Use the expression below to answer the question. Select all expressions that are equivalent.

Mathematics

1 answer:

lukranit [14]3 years ago

8 0

Answers: All the expressions that are equivalent to -y -1 are A and E.

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Which is the approximate mass of a button?

pav-90 [236]

<span>I narrowed it down to C or D because all the other options are not ways of measuring mass of a physical mass such as a button, and I have concluded the answer is C. 1 kilogram</span>

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4 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ipn [44]

It has been a good while since I have done this type of work so I am deeply sorry if I am wrong.

The experimental probability of rolling an odd number is around 683.3333%, which is 58.3333% more than the theoretical probability.

Again I am deeply sorry if I am wrong, have a good rest of your day!

8 0

3 years ago

Read 2 more answers

From the sum of 3x^2-5x+1 and x^3 +3x - 1 subtract 2x^3 - 4x2

Mariana [72]

Answer:

it is -x^3 + 7x^2 -2x if you meant subtract 2x^3 - 4x^2 But if you meant subtract. 2x^3 - 4x +2 then the answer is -x^3 +3x^2 +2x -2

Step-by-step explanation:

5 0

3 years ago

A triangular section of land is fenced off due to contamination. Two sides of the triangle are each 16 meters ( 16m) longer than

Sphinxa [80]

Answer: the shortest side is 30m

Step-by-step explanation:

Let the shortest side be a meters

If side 2 is 16m longer than the shortest side, then it is (16+a)meters.

The same goes with side 3.

Then,

a + (16+a) + (16+a) = 122m

32 + 3a = 122m

Collecting like terms together,

3a = 122 - 32

3a = 90

Divide by coefficient of a

3a/3 = 90/3

a = 30 meters

Check:

30 + (16+30) + (16+30)

30 + 46 + 46 = 112

8 0

4 years ago

Read 2 more answers

For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l

murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

$X_i \sim \frac{G_1}{2}$

$E(X_i)=2 \\$

$Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\$

$= \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2$

Now we calculate the $\bar X \sim N(2, \sqrt{\frac{2}{n}})\\$

$\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}} \sim N(0, 1)\\$

$\to \sum^n_{i=1} \frac{X_i - 2}{n} \times\sqrt{\frac{n}{2}}} \sim N(0, 1)\\\\\to \sum^n_{i=1} \frac{X_i - 2}{\sqrt{2n}} \sim N(0, 1)\\$

$\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\$

$\to P(-1 \leq X_n \leq 2) = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\$

$= 0.92 -0.24\\\\= 0.68$

6 0

3 years ago