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Marina CMI [18]
3 years ago
9

Y=? What is Y? Please help me!

Mathematics
2 answers:
kumpel [21]3 years ago
7 0
Answer:   y = 6 mi.  .
______________________________________________
Explanation:
______________________________________________
Area of a triangle = (½) * (base) * (height) ;

or,  A = (½) * b * h ;  or,  A = b*h / 2 ;
_____________________________________
Given:  A = 24.3 mi ² ;
           b = 8.1 mi 
___________________
Find the height, "h" ;  (in units of "miles", or , "mi" ).
__________________________
   Plug in the known values into the formula:

24.3 mi ² = (½) * (8.1 mi) *(h) ;
_____________________________
Solve for "h" (height) ;
_____________________________
(½) * (8.1 mi) = 4.05 mi  ;
______________________________
Rewrite: 
____________________________
24.3 mi² = (4.05 mi) *(h) ;  Solve for "h" ;
_________________________________________
 Divide each side of the equation by "(4.05 mi)" ; to isolate "h" on one side of the equation ; and to solve for "h" ; 
__________________________________________
   24.3 mi²  / 4.05 mi  = (4.05 mi) *(h)  / 4.05 mi ;
                                 
              →  6 mi  = h ;  ↔  h = 6 mi. 

              →      h = y = 6 mi. 
____________________________________________
Anna11 [10]3 years ago
7 0
I'd suggest you begin with the formula for the area of a triangle of base b and height h.  It is as follows:

         bh
A = --------
          2

Here b is the length of the base and h is the height of the triangle.
In this problem the area and the base are given; they are 24.3 square miles and 8.1 miles respectively. We are to determine the height, y.

                                                                                          2A  
Solve the above equation for h, the height:  2A=bh, or  -------
                                                                                            b

Substitute (24.3 square miles) for A and 8.1 miles for b.

Calculate y (or, equivalently, calculate h).  Both represent the height of the given triangle.
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Determine the margin of error, m m , of a 90% confidence interval for the mean IQ score of all students with the disorder. Assum
Vsevolod [243]

Answer:

The margin of error is 6.45.

Step-by-step explanation:

The complete question is:

As an early intervention effort, a school psychologist wants to estimate the average score on the Stanford-Binet Intelligence Scale for all students with a specific type of learning disorder using a simple random sample of 36 students with the disorder.

Determine the margin of error, of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume that the standard deviation IQ score among the population of all students with the disorder is the same as the standard deviation of IQ score for the general population, σ = 15 points.

The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:

CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

Given:

<em>n</em> = 36

σ = 15

(1 - <em>α</em>)% = 99%

Compute the critical value of <em>z</em> for 99% confidence level as follows:

z_{\alpha/2}=z_{0.01/2}=z_{0.005}=2.58

*Use a <em>z</em>-table.

Compute the value of MOE as follows:

MOE= z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}

          =2.58\times\frac{15}{\sqrt{36}}

          =2.58\times 2.5\\=6.45

Thus, the margin of error is 6.45.

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3 years ago
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KiRa [710]

Answer:

1. n + 7 ≤ 9

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1 year ago
Colin scored 16 and Brian scored 63 more than Colin.What was their combined score?
kodGreya [7K]

Answer:

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Step-by-step explanation:

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3 years ago
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assuming the scale is by 1,

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4 years ago
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