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3 years ago

Someone help please

Mathematics

2 answers:

GarryVolchara [31]3 years ago

8 0

C.
4 (x+7) = 38 represents the tape diagram correctly.

tatyana61 [14]3 years ago

8 0

You are doin k12

Answer: so the answer should be (C)

Step-by-step explanation: i hope i'm correct cause i'm in 7th grade.

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Distribute (x-6)(x-7) a) x^2-13x-15 b) x^2-13x+42 c) x^2+x+42 d) x^2+x-15

Sidana [21]

Answer:

B. x² - 13x + 42

Step-by-step explanation:

7 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Find the lim a to b idk hiw to do it

Elina [12.6K]

$\bf \lim\limits_{a\to b} \cfrac{a^2-3ab+2b^2}{a-b}\implies \lim\limits_{a\to b} \cfrac{(a-1b)(a-2b)}{a-b}
\\\\\\
\lim\limits_{a\to b} \cfrac{\underline{(a-b)}(a-2b)}{\underline{a-b}}
\implies 
\lim\limits_{a\to b} a-2b\implies \lim\limits_{a\to b} b-2b\implies \lim\limits_{a\to b}-b$

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3 years ago

Which of the following is a polynomial function in factored form with zeros at –2, 5, and 8?

Usimov [2.4K]

(x + 2)(x - 5)(x - 8)
Substitute them into each other to get the whole equation)

7 0

4 years ago

Joaquin lives 0.3 miles from Kaeith. Layla lives 0.4 times as far from Keith as Joaquin, How far does Layla live fromKeith? Writ

Kipish [7]

Well you would subtract 0.4 by 0.3 and get 0.1. So 0.1 is your answer

5 0

3 years ago

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