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3 years ago

I need help simplifying -11+5b+6-2b

2 answers:

6 0

(-11)+[5b]+(6)+[-2b]
Take the like terms, for example, -2b and 5b since they share the variable b, and add them together (3b). Then take the other terms, 6 and -11, and add them together [-5]. The terms with a variable usually go first in the equation, so your equation would be:
3b+-5 or 3b+(-5)

REY [17]3 years ago

5 0

You take 5b and -2b which will make: 3b
then combine -11 and 6 to get: -5
full answer: 3b-5

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21/24 reduced fraction

svetoff [14.1K]

21/24
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3 years ago

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Find the area and perimeter of the shaded figure

puteri [66]

Answer:

Area - 6 unit^2 Perimeter - 10 units

Step-by-step explanation:

The shaded figure is 3 units long and 2 units high.

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3 years ago

A rectangular box without a top is have a volume of 12 cubic feet. Find the dimensions of

LiRa [457]

If the length, breadth and height of the box is denoted by a, b and h respectively, then V=a×b×h =32, and so h=32/ab. Now we have to maximize the surface area (lateral and the bottom) A = (2ah+2bh)+ab =2h(a+b)+ab = [64(a+b)/ab]+ab =64[(1/b)+(1/a)]+ab.

We treat A as a function of the variables and b and equating its partial derivatives with respect to a and b to 0. This gives {-64/(a^2)}+b=0, which means b=64/a^2. Since A(a,b) is symmetric in a and b, partial differentiation with respect to b gives a=64/b^2, ==>a=64[(a^2)/64}^2 =(a^4)/64. From this we get a=0 or a^3=64, which has the only real solution a=4. From the above relations or by symmetry, we get b=0 or b=4. For a=0 or b=0, the value of V is 0 and so are inadmissible. For a=4=b, we get h=32/ab =32/16 = 2.

Therefore the box has length and breadth as 4 ft each and a height of 2 ft.

4 0

3 years ago

PLS HELP ASAP I DONT HAVE TIME FOR THIS, IT ALSO DETECTS IF ITS RIGHT IR WRONG

Veronika [31]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

Can you help with this please.

andrew-mc [135]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - two points P ( 5 , 10 ) and R ( 12 , 14 ) on the cartesian plane

To find - distance between the two points

Using the distance formula ~

$\qquad\underline{d(PR) = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }} \\ \\$

we have ,

$\longrightarrow x_{1} = 5 \\ \longrightarrow x_{2} = 12 \\ \\ \longrightarrow \: y_{1} = 10 \\ \longrightarrow \: y_{2} = 14$

substituting the values in the formula , we get

$d(PR) = \sqrt{(12-5) {}^{2} + (14-10) {}^{2} } \\ \\ \implies \: d(PR) = \sqrt{(7) {}^{2} + ( 4) {}^{2} } \\ \\ \implies \: d(PR) = \sqrt{49 + 16} \\ \\ \implies \: d(PR) = \sqrt{65} \\ \\ \implies \: d(PR) = 8.1 \: units \: (approx)$

hope helpful :)

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2 years ago

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