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4 years ago

Ava buys a carousel that is 80% off, if Ava pays $36 what was the original price

Mathematics

2 answers:

dmitriy555 [2]4 years ago

6 0

$45 hope this helps you

Airida [17]4 years ago

5 0

Answer: $45

Step-by-step explanation:

Let the original rice of the carousel = $x

Therefore cost Price = $36

Discount is 80% of the original price $x = $36

To calculate x , we find 80% of $x and equate to $36

= ⁸⁰/₁₀₀ ˣ $x

= 80x/100

80x/100 = 36

Now, multiply through by 100 and divide by 80

80x = 3600

x = $45.

The original price of the carousel = $45.

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Answer:

26.55

Step-by-step explanation:

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use the b^2 equation

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b^2 = 31 squared - 16 squared.

b^2 = 705

b= $\sqrt{705}$

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3 years ago

In ΔABC, the measure of ∠C=90°, the measure of ∠A=40°, and BC = 2.6 feet. Find the length of CA to the nearest tenth of a foot.

vladimir1956 [14]

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3 years ago

The perimeter of a sand volleyball court is 48 meters. It is 8 meters wide. How long is it?

zysi [14]

16 meters

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3 years ago

How many plastic cubes can fit into the box?

netineya [11]

Option D:

160 plastic cubes can fit into the box.

Solution:

Convert mixed fraction into improper fraction.

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Width of the box = $2\frac{1}{2}=\frac{5}{2}$ ft

Height of the box = 2 ft

Volume of the box = length × width × height

$$=4\times\frac{5}{2} \times2$

= 20 ft³

Volume of the box = 20 ft³

Length of the plastic cube = $\frac{1}{2}$ ft

Volume of the cube = length × length × length

$$=\frac{1}{2} \times\frac{1}{2} \times\frac{1}{2}$

$$=\frac{1}{8} \ \text{ft}^3$

Volume of the cube = 0.125 ft³

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$$=\frac{20}{0.125}$

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Hence 160 plastic cubes can fit into the box.

Option D is the correct answer.

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3 years ago

The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act

cluponka [151]

Answer: 0.3061.

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean $\mu$ , the actual temperature of the medium, and standard deviation $\sigma$ .

Let X be the random variable that represents the reading of the thermometer.

Confidence level : $=95\%$

We know that the z-value for 95% confidence interval is 1.96.

Then, we have

$-1.96$ $z=\dfrac{X-\mu}{\sigma}$

$\Rightarrow\ -1.96\sigma$

But all readings are within 0.6° of $\mu$ .

So, $1.96\sigma=0.6$

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Hence, the required standard deviation will be

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3 years ago