Answer:
Step-by-step explanation:
we know that
The value of sine of an angle in a right triangle is equal to the opposite side of the angle divided by the hypotenuse
so
Answer:
yes
Step-by-step explanation:
Substitute x = 2 and y = 5 into the left side of the equations and if equal to the right side then they are a solution.
x + 2y = 2 + 2(5) = 2 + 10 = 12 ← True
3x + 6y = 3(2) + 6(5) = 6 + 30 = 36 ← True
Thus x = 2, y = 5 is a solution to both equations
Step-by-step explanation:
<h2>
Step-by-step explanation:1) Irrational number</h2><h2>
2) Irrational number</h2><h2>
3) Irrational number</h2><h2>
4) Rational Number</h2>
For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4
Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1
Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20
Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3
Answer:
i think its the last option.
Step-by-step explanation:
its not the first one because they it can be proved using AAS (but that option isnt available)
You can't prove it with SSS or ASA without more info
AAA doesn't exist
theirfore it must be the last option.
