In ΔABC, the measure of ∠C=90°, the measure of ∠A=40°, and BC = 2.6 feet. Find the length of CA to the nearest tenth of a foot.
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Answer:
Step-by-step explanation:
Product of slope of perpendicular lines = -1
6x + 5y = 30
Write this equation in y = mx + b form
5y = -6x + 30
y =
Slope of this line m₁ = -6/5
m₁ * m₂ = -1
m₂ = -1÷m₁ = -1 *
& (-6 , -7)
Equation of the required line: y - y₁ = m (x - x₁)