1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksivusya [100]
3 years ago
7

Write the following parametric equations as a polar equation x=t^2 y=2t

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

r=4\csc \theta \cot\theta

Step-by-step explanation:

The given parametric equations are;

x=t^2

y=2t

We make t the subject in the second equation to get:

t=\frac{y}{2}

We substitute into the first equation to get:

x=(\frac{y}{2})^2

We use the relation:

x=r\cos \theta and y=r\sin \theta

r\cos \theta=(\frac{r\sin \theta}{2})^2

r\cos \theta=\frac{r^2\sin^2 \theta}{4}

r=4\csc \theta \cot\theta

You might be interested in
5,698+12,326 is even number are odd number
Elden [556K]

Answer: Even

Step-by-step explanation:

Look at the ones place of each number, which in this case is 8 and 6.

8 + 6 = 14, which is an even number. This makes the sum of both numbers also an even number.

6 0
2 years ago
Read 2 more answers
Using the Law of Cosines, in triangle DEF, if e=18yd, d=10yd, f=22yd, find measurement of angle D
Ivahew [28]
Check the picture below.

\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}
\\\\\\
\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\
-------------------------------\\\\
\begin{cases}
d=10\\
e=18\\
f=22
\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D

\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D

7 0
3 years ago
Find the area of the semicircle. diameter = 12
dimaraw [331]

Answer:

\huge\boxed{\sf Area\ of \ Semicircle = 56.55 \ units^2}

Step-by-step explanation:

Diameter = 12

Radius = 12/2 = 6

\sf Area\ of \ Semicircle =\frac{\pi r^2}{2} \\Area\ of \ Semicircle =\frac{\pi (6)^2}{2} \\Area \ of \ Semicircle = \frac{\pi (36)}{2}\\ Area \ of \ Semicircle = 18 \ pi

\sf Area\ of \ Semicircle = 56.55 \ units^2

7 0
3 years ago
Read 2 more answers
The length of a rectangle has a measure of x and the width of a rectangle has a measure of (x-2). Find x if the area is 35.
Oliga [24]

Answer:

length = 7

pls mark me the brainliest

Step-by-step explanation:

A = Lw

35 = x (x -2)

35 = x2 - 2x

x2 -2x -35 = 0

(x-7)(x+5) = 0  

x-7=0

x=7       (we won't use the other factor since it would give us a negative length

so length = 7

4 0
3 years ago
Alex wants to paint one side of his skateboard ramp with glow-in-the-dark paint, but he needs to know how much area he is painti
Svetach [21]
The answer of the question is 140. hope i help you ;)

8 0
3 years ago
Read 2 more answers
Other questions:
  • On the first day, a company has 64 orders for shipping crates on backorder. Every day customers order 18 more shipping crates. I
    11·1 answer
  • In a certain class , 7/10 of the students got problem 15 wrong on Friday's math test.
    6·1 answer
  • there was a total of 750 and 2015 crickets in a pond, the population increased by 17% the next year. The year after that the pop
    12·2 answers
  • Complete the steps to find the area of the trapezoid.
    9·2 answers
  • 3(32 − 4 + 6 )− (82 + + 3) ?<br> simpilyfy<br> plzz
    11·2 answers
  • Find the 79th term of the following sequence 3,9,15,21
    11·1 answer
  • Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 w
    10·1 answer
  • 14. A quadratic equation is graphed above.
    7·1 answer
  • (-8)–(-13)? Answer plz
    9·2 answers
  • Which statements are true? and whos down to talk?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!