The number of 11-inch softball is 70 and the number of 12-inch softball is 50.
<u>Step-by-step explanation</u>:
<u>Given that,</u>
- The cost of 11-inch softball = $2.50
- The cost of 12-inch softball = $3.50
<u>Let us assume,</u>
- The number of 11-inch softball be 'x'.
- The number of 12-inch softball be 'y'.
<u>Forming the equation to solve x and y values :</u>
- The total number of softball ordered = 120
- The total cost for 120 softballs = $350
x + y = 120 -------(1)
2.5x + 3.5y = 350 --------(2)
<u>Multiply eq(1) by 2.5 and subtract eq(2) from eq(1)</u>,
2.5x +2.5y = 300
-<u>(2.5x +3.5y = 350)</u>
<u> -1y = -50</u>
Therefore the value of y = 50.
The number of 12-inch softball is 50.
<u>Substitute y=50 in eq(1),</u>
x+50 = 120
x = 120-50
x = 70
The number of 11-inch softball is 70.
Answer:
(12.1409, 14.0591
Step-by-step explanation:
Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.
Group Group One Group Two
Mean 87.600 74.500
SD 1.000 1.500
SEM 0.316 0.433
N 10 12
The mean of Group One minus Group Two equals 13.100
standard error of difference = 0.556
90% confidence interval of this difference:

t = 23.5520
df = 20
Answer:
Greater than.
Step-by-step explanation:
8.6 is greater than -8
No,The room is not a square shaped.This is because.Perimeter of the square shape would be length of any sides×4 as all sides will be the same in a square.Therefore, if the room ia a square, the 4 sides of room floor will be equal too.It is not a square shaped room beacause it sides are not equal for floor.We can determine by finding the sides;
diagonal is 18.75 so by using pythagoras theorem
diagonal^2 =l^2 + b^2
b^2=18.75^2 + 17^2
b =25.31 inches which is not the same as the length 17 inches.Therefore,the room is not a square
I do not see an answer, only because Zach's change in reading time increases exponentially, and Victoria's increases at a linear rate.