I can’t figure out what math to do for problem #2
1 answer:
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Answer:
Option 1.1
Step-by-step explanation:
The linearization of a curve implies the use of calculus to find the local value for the derivative and approximating the function by the use of the formula
The function is given in such way that it's much easier to find the derivative by implicit differentiation than isolating any of the variables
Differentiating with respect to x, we have
Computing y' in the given point (3,1) we have
4(3)(1)+2(9)y'+y'=2
The function will be approximated with the expression
To find the approximate value for x=2.8
The correct value is the option 1.1
Answer:
The other midpoint is located at coordinates (-9,-2) (Second option)
Step-by-step explanation:
<u>Midpoints</u>
If P(a,b) and Q(c,d) are points in , the midpoint between them is the point exactly in the center of the line that joins P and Q. Its coordinates are given by
We are given one endpoint at P(1,-2) and the midpoint at M(-4,-2). The other endpoint must be at an equal distance from the midpoint as it is from P. We can see both given points have the same value of y=-2. This simplifies the calculations because we only need to deal with the x-coordinate.
The x-distance from P to M is 1-(-4)=5 units. This means the other endpoint must be 5 units to the left of M:
x (other endpoint)= - 4 - 5 = - 9
So the other midpoint is located at (-9,-2) (Second option)