Use pythagorean theorem for all of them
a. 3, 4, 5
3^2+4^2?5^2
9+16?25
25=25
right
b. 5, 6, 7
5^2+6^2=7^2
25+36=49
61>49
acute
c. 64+81=144
145>144
acute
hope this helps!
Answer:
Step-by-step explanation:
![We\ are\ given\ that,\\Line\ YZ\ ||\ ZW\\\angle XYM=90\\Hence,\\Line\ Segment\ XY\ being\ the\ transversal,\ cuts\ YZ\ and\ XW.\\Hence,\\We\ know\ that\\The\ set\ of\ co-interior\ angles [Interior\ angles\ on\ the\ same\ side\\ of the\ transversal]\ are\ supplementary.\\Hence,\\Here,\\The\ pair\ of\ co-interior\ angles\ formed\ are\ \angle XYZ\ and\ \angle YXW.\\Hence,\ they\ are\ supplementary\ too.\\Hence,\\\angle XYZ\ + \angle YXW= 180\\Hence, by\ substituting\ XYZ=90+2x,\angle YXW=3x-5](https://tex.z-dn.net/?f=We%5C%20are%5C%20given%5C%20that%2C%5C%5CLine%5C%20YZ%5C%20%7C%7C%5C%20ZW%5C%5C%5Cangle%20XYM%3D90%5C%5CHence%2C%5C%5CLine%5C%20Segment%5C%20XY%5C%20being%5C%20the%5C%20transversal%2C%5C%20cuts%5C%20YZ%5C%20and%5C%20XW.%5C%5CHence%2C%5C%5CWe%5C%20know%5C%20that%5C%5CThe%5C%20set%5C%20of%5C%20co-interior%5C%20angles%20%5BInterior%5C%20angles%5C%20on%5C%20the%5C%20same%5C%20side%5C%5C%20of%20the%5C%20transversal%5D%5C%20%20are%5C%20supplementary.%5C%5CHence%2C%5C%5CHere%2C%5C%5CThe%5C%20pair%5C%20of%5C%20co-interior%5C%20angles%5C%20formed%5C%20are%5C%20%5Cangle%20XYZ%5C%20and%5C%20%5Cangle%20YXW.%5C%5CHence%2C%5C%20they%5C%20are%5C%20supplementary%5C%20too.%5C%5CHence%2C%5C%5C%5Cangle%20XYZ%5C%20%2B%20%5Cangle%20YXW%3D%20180%5C%5CHence%2C%20by%5C%20substituting%5C%20XYZ%3D90%2B2x%2C%5Cangle%20YXW%3D3x-5)
100/12=8⅓
multiply the other numbers by 8⅓ to get
15*8⅓=125
21*8⅓=175
the lengths are 100,125,175
Answer:
Step-by-step explanation:
Let x be the random variable representing the number of miles that each person walked each day for 6 months. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,
z = (x - µ)/σ
Where
x = sample mean
µ = population mean
σ = standard deviation
For Rueben,
µ = 5
σ = 1.1
the probability that Rueben walked more than 6.1 miles is expressed as
P(x > 6.1) = 1 - P( x ≤ 6.1)
For x = 6.1,
z = (4 - 6.1)/1.1 = - 1.91
Looking at the normal distribution table, the probability corresponding to the z score is 0.02807
P(x > 6.1) = 1 - 0.02807 = 0.97193
P(x > 6.1) = 0.97 × 100 = 97%
For Victor,
µ = 4.4
σ = 1.4
the probability that Victor walked less than 5.8 miless is expressed as
P(x < 5.8)
For x = 5.8,
z = (5.8 - 4.4)/1.4 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x < 5.8) = 0.84 = 84%
Answer:
point of intersection = (0.94,11.22)
