With what? have an image or something of the question?
30043——————3.0043 x 10^4
30.043—————— 3.0043 x10^1
0.0030043—————-3.0043 x 10^-3
0.30043—————-3.0043 x 10^-1
3.0043————-3.0043 x 10^0
Hope this helps please mark brainiest
The domain of the function is D ∈ R or (-∞, ∞) and the range of the function is R ∈ (591.39, ∞)
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
f(x) = -4.92x² + 17.96x + 575
The above function is a quadratic function and we know,
The quadratic function domain is all real numbers.
The domain of the function is all real numbers or
D ∈ R or (-∞, ∞)
The range:
From the graph of a function:
The maximum value of the graph:
f(1.825) = 591.39
So the range of the function:
R ∈ (591.39, ∞)
Thus, the domain of the function is D ∈ R or (-∞, ∞) and the range of the function is R ∈ (591.39, ∞)
Learn more about the function here:
brainly.com/question/5245372
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Kx-3y=k
y=4x+1 ( we will put it in 1st equation )
kx - 3 (4x+1)=k
kx - 12 x - 3 =k
kx - 12 x = k+3
x(k-12) = k+3
x=

Also y=

We can not divide with zero.
k-12=0
k=12For k= 12 equations have no solutions.
Answer: x^2 + y^2 -10y = 0
Step-by-step explanation:
Cartesian coordinates, also called the Rectangular coordinates, isdefined in terms of x and y. So, for the problem θ has to be eliminated or converted using basic foundations that are described by the unit circle and the right triangle trigonometry.
r= 10sin(θ)
Remember that:
x= r × cos(θ)
y= r × sin(θ)
r^2= x^2 + y^2
Multiply both sides of the equation by r. This will give:
r × r = 10r × sin(θ)
r^2 = 10r × sin(θ)
x^2 + y^2= 10r × sin(θ)
Because y= r × sin(θ), we can make a substitution. This will be:
x^2 + y^2= 10y
x^2 + y^2 -10y = 0
The above equation is the Rectangular coordinate equivalent to the given equation.