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Flura [38]
3 years ago
8

Can someone help me please ? Thanks!

Mathematics
2 answers:
notka56 [123]3 years ago
6 0
Use pythagorean theorem for all of them
a. 3, 4, 5
3^2+4^2?5^2
9+16?25
25=25
right 

b. 5, 6, 7
5^2+6^2=7^2
25+36=49
61>49
acute

c. 64+81=144
145>144
acute

hope this helps!
Furkat [3]3 years ago
5 0
I will give you the general approach and you can do the calculations by yourself.

Assume 3 vertices are a,b,c

if a^2 + b^2 < c^2 ->it's obtuse

a^2 + b^2 = c^2 ->it's right

a^2 + b^2 > c^2 ->it's acute

First one is right apparently, similar combination of right triangle include 6,8,10
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Answer:

A gasoline tank for a certain car is designed to hold 14.0 gal of gas.

\mu = 14

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z=\frac{x-\mu}{\sigma}

z=\frac{13.7-14}{0.2}

z=-1.5

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p value = 0.0668

So, P(x \leq 13.7)= 0.0668

The probability that a randomly selected tank will hold at most 13.7 gal is  0.0668

b)What is the probability that a randomly selected tank will hold between 13.4 and 14.3 gal?

We are supposed to find P(13.4

z=\frac{x-\mu}{\sigma}

z=\frac{13.4-14}{0.2}

z=-3

P(x<13.4)=P(z<-3)= 0.0013

z=\frac{x-\mu}{\sigma}

z=\frac{14.3-14}{0.2}

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P(13.4

The probability that a randomly selected tank will hold between 13.4 and 14.3 gal is 0.9319

(c) If two such tanks are independently selected, what is the probability that both hold at most 14 gal?

We are supposed to find P(x \leq 14)

z=\frac{x-\mu}{\sigma}

z=\frac{14-14}{0.2}

z=0

Refer the z table for p value

p value = 0.5

So, P(x \leq 14)= 0.5

Two such tanks are independently selected, the probability that both hold at most 14 gal = 0.5 * 0.5 = 0.25

Hence If two such tanks are independently selected, the probability that both hold at most 14 gal is 0.25

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3 years ago
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olganol [36]
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3 years ago
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Elena L [17]

Answer:

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