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3 years ago

Can someone help me please ? Thanks!

Mathematics

2 answers:

notka56 [123]3 years ago

6 0

Use pythagorean theorem for all of them
a. 3, 4, 5
3^2+4^2?5^2
9+16?25
25=25
right

b. 5, 6, 7
5^2+6^2=7^2
25+36=49
61>49
acute

c. 64+81=144
145>144
acute

hope this helps!

Furkat [3]3 years ago

5 0

I will give you the general approach and you can do the calculations by yourself.

Assume 3 vertices are a,b,c

if a^2 + b^2 < c^2 ->it's obtuse

a^2 + b^2 = c^2 ->it's right

a^2 + b^2 > c^2 ->it's acute

First one is right apparently, similar combination of right triangle include 6,8,10

You might be interested in

1/2x+2 in linear equation

Bogdan [553]

x/2+2 = 0

x+4/2 = 0

x+4 = 0

4 0

3 years ago

HELP ME PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS URGENTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

bazaltina [42]

9514 1404 393

Answer:

90 m²

Step-by-step explanation:

The given linear dimensions have the ratio ...

red/blue = (6 m)/(4 m) = 3/2

The ratio of areas is the square of the ratio of the linear dimensions:

(red area)/(blue area) = (3/2)²

S = (blue area)(9/4) = (40 m²)(9/4)

S = 90 m²

5 0

2 years ago

If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes

anyanavicka [17]

ANSWER

$x = 2 \: \: or \: \: x = 15$

$x = - 2 \: \: or \: \: x = - 15$

EXPLANATION

The given polynomial is

$f(x) = {x}^{2} + kx + 30$

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

$m + n = - \frac{b}{a} = -k$

and the product of roots is

$mn = \frac{c}{a} = 30$

The square difference of the zeroes is given by the expression.

$( {m - n})^{2} = {(m + n)}^{2} - 4mn$

From the question, this difference is 169.

This implies that:

$( { - k)}^{2} - 4(30) = 169$

${ k}^{2} -120= 169$

$k^{2} = 289$

$k= \pm \sqrt{289}$

$k= \pm17$

We substitute the values of k into the equation and solve for x.

$f(x) = {x}^{2} \pm17x + 30$

$f(x) = (x \pm2)(x \pm 15)$

The zeroes are given by;

$(x \pm2)(x \pm 15) = 0$

$x = \pm2 \: \: or \: \: x = \pm 15$

5 0

3 years ago

M is directly proportinal to r^2 when r = 2 m= 14 work out the value of m

attashe74 [19]

Answer:

14?

Step-by-step explanation:

4 0

3 years ago

Someone pls help me.

nydimaria [60]

I’m here to help.
For this question here you need to use the sine formula for the area of a triangle and figure out the area of the sector

I’ll take you through it step-by-step

Area of the arc:

We only have 68.9 degrees out of 360 and we need to use the formula for the area of a circle.
Formula of a circle = pi x radius squared

68.9/360 x pi x 86.1184= 51.78 (2dp)

Area of triangle:
As you can see we have no height so we must use the sine formula for the area of a triangle.
Formula= 1/2abSinC

You should end up with
0.5 x 9.28x 9.28 x Sin(68.9)= 40.17 (2dp)

Now since you want the area of the segment shaded, just find the difference between these two values.

51.78-40.17 = 11.61
Answer= 11.6cm squared

Hope this helped!

3 0

3 years ago