Question

Anton pushes a table across the floor with a force of 6 N. Suppose the table has a mass of 6 kg and he pushes the table for 2 seconds. What is the acceleration of the table?
What is the change in velocity from the time he begins pushing to when he stops pushing? Explain.

Answer 1

We can use this formula to solve for acceleration of the table
F = ma
We are given with the force and the mass, so
6 N = 6 kg a
a = 1 m/s2

The change in velocity can be solve using this formula
FΔt = mΔv
6N (2s) = (6 kg) (Δv)
Δv = 2 m/s

Answer 2

Hello there.

Anton pushes a table across the floor with a force of 6 N. Suppose the table has a mass of 6 kg and he pushes the table for 2 seconds. What is the acceleration of the table?

 2 m/s