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goldfiish [28.3K]

2 years ago

8

Identify the number as rational or irrational. Explain. 291.87

1 answer:

ludmilkaskok [199]2 years ago

7 0

I believe it would be irrational cause it is written as a decimal and is not repeating.

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The parent function f(x) = x3 and its translation, g(x), are shown on the graph.

NNADVOKAT [17]

The resulting function g(x) = (x-5)^3 + 3 shows a horizontal translation to the right by 5 units and vertical translation up by 3 units

<h3>Translation of functions</h3>

Quadratic functions are functions that has a leading degree of 2.

Given the parent function as shown:

f(x) = x^3

The resulting function g(x) = (x-5)^3 + 3 shows a horizontal translation to the right by 5 units and vertical translation up by 3 units

Learn more on translation here; brainly.com/question/12861087

#SPJ1

5 0

1 year ago

25 cm of ribbon at £2.20 per metre what is the cost

Step2247 [10]

0.55 pence or quid per 25 centimeters as if you multiply it by 4 it would be 2.20 pound because 1 metre is 100 centimeters after i divide 100 by 25 i get 4 which would be 1/4 which i would then multiply 1/4 x 2.2 pound

3 0

2 years ago

Please help me find the slope of the line !!

LenaWriter [7]

The slope of the line is 3/2. That would be letter B. You take two points from the graph and subtract them from each other to find the slope. Hope this helps!

3 0

2 years ago

Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

2 years ago

Read 2 more answers

A rectangle has a perimeter of 56 in. The length is four more than the width. What are the length and width of the rectangle

Aleks04 [339]

Answer:

Width = 12 in

Length = 16 in

Step-by-step explanation:

Let, the Width of the rectangle = w in

Now, the length of the rectangle = (w + 4) in

Now, Perimeter = 56 in

Also, we know that

Perimeter of the Rectangle = 2 (Length +Width)

or, 2 (Length +Width) = 56

⇒ 2(w + 4 +w) = 56

or, 4w =56 -8

width = 12 in

So, Length = w + 4 = 12 + 4 = 16 in

7 0

2 years ago