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3 years ago

8

The graph represents the linear relationship between the number of books Layla has read and the number of months she has been a

member of a book club

2 answers:

zhannawk [14.2K]3 years ago

8 0

Answer:

G

Step-by-step explanation:

stira [4]3 years ago

7 0

The answer is G! Hope I helped:)

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Which expression is equivalent to square root 55x^7y6/11x^11y^8

Novay_Z [31]

Answer:

$\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}$

Step-by-step explanation:

$\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a$

$=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}$

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2 years ago

Simplify -1/4m + 5/6 +3/8m - 2/3 <br><br><br><br><br> HURRYYY PLEASE !!!!

sukhopar [10]

3/8 m - 1/4 m + 5/6 - 2/3

3/8 m - 2/8 m + 5/6 - 4/6

<u>1/8 m</u><u> + </u><u>1/6</u>

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2 years ago

What would the decimal number 20 be in binary?

Inessa05 [86]

<span>10100 is the answer hope it helps you.

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3 years ago

(2+2w)⋅4+9(w+3) please answer this I am very confused

defon

Answer:

17w+35

Step-by-step explanation:

(2+2w)⋅4+9(w+3)

Distribute the 4 and the 9

2*4 + 2w*4 +9*w+9*3

8+8w +9w +27

Combine like terms

8w+9w +8+27

17w +35

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2 years ago

Read 2 more answers

aalyn [17]

Answer:

Step-by-step explanation:

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2 years ago