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egoroff_w [7]
2 years ago
13

film processing costs $4.95, plus $0.35 for each picture printed. Milan paid $11.95 for processing and printing. How many pictur

es did he have printed?
Mathematics
1 answer:
xenn [34]2 years ago
7 0

Answer:

20 pictures.

Step-by-step explanation:

In this question, we need to find out how many pictures Milan printed.

We know that the film processing costed $4.95 and each picture that was printed costed $0.35.

Lets turn this into an equation with x representing the amount of pictures:

y = 0.35x+ 4.95

Now we need to solve the equation. We can do this by plugging in our known cost, 11.95, into "y".

Solve:

11.95 = 0.35x + 4.95

Subtract 4.95 from both sides.

7 = 0.35x

Divide both sides by 0.35

20 = x

Milan printed 20 pictures.

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denis-greek [22]
100-35 = 65
65% de 2300 = 1495 (mes 1)
2300-1495 = 805 (mes 2)
65% de 805 = 523,25 (mes 3)
65% de 523,25 = 340,1125 ~ 340,10 (mes 4)
8 0
3 years ago
PLEASE HELP!!!! THANKS!!!! (WILL MARK BRAINLIEST)
Lelechka [254]

Answer:11/26=0.423076923077 so it could be .0423

Step-by-step explanation:

7 0
2 years ago
a statistics professor finds that when he schedules an office hour at the 10:30a, time slot, an average of three students arrive
Veseljchak [2.6K]

Answer:

The probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

Step-by-step explanation:

Let <em>X</em> = number of students arriving at the 10:30 AM time slot.

The average number of students arriving at the 10:30 AM time slot is, <em>λ</em> = 3.

A random variable representing the occurrence of events in a fixed interval of time is known as Poisson random variables. For example, the number of customers visiting the bank in an hour or the number of typographical error is a book every 10 pages.

The random variable <em>X</em> is also a Poisson random variable because it represents the fixed number of students arriving at the 10:30 AM time slot.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.

The probability mass function of <em>X</em> is given by:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...,\ \lambda>0

Compute the probability of <em>X</em> = 2 as follows:

P(X=2)=\frac{e^{-3}3^{2}}{2!}=\frac{0.0498\times 9}{2}=0.2241

Thus, the probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.

6 0
3 years ago
Read 2 more answers
How to find the angle?
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If everything on inside of a line is 180->
(Line) --------/---------- everything on top equals 180 and there should be a number on either side. For instance 180-50 for the top would be 130, the wide angle's angle. I answer everything I like and come across so sorry I am four weeks late.
4 0
3 years ago
Rating Frequency Present Frequency Excellent 18 _______Very Good 25 _______Good 4 _______Fair 1 2Poor 2 4 Total 50 100What do th
nata0808 [166]

Answer:

a) Rating Frequency Percent Frequency

Excellent 18 ___36%____Very Good 25 ___50%____Good 4 ___8%____Fair 1   2% Poor 2  4%  Total 50 100 What do these summaries indicate about the overall customer satisfaction with the Delta flight? ____94%______ % customers are satisfied with the Delta Flight Et either a good, very good, or excellent rating. Only ____6%_______% of customers rated the Delta flight Fair or Poor.

b. The online survey questionnaire enabled respondents to explain any aspect of the flight that Failed to meet expectations. Would this be helpful information to a manager looking for ways to improve the overall customer satisfaction on Delta flights? Explain.

Allowing survey respondents to explain their 5-point scale responses would provide helpful information to managers looking for ways to improve customer satisfaction on Delta flights. The ____6______% respondents indicating that the flight failed to meet expectations would have the opportunity to provide detailed information about their expectations.

Step-by-step explanation:

a) Data and Calculations:

                  Rating Frequency     Percent Frequency

Excellent                18                       ____36%___

Very Good            25                       ____50%___

Good                       4                       ____  8%___

Fair                          1                        ____  2%___

Poor                        2                       _____4% __

Total                     50                               100%

b) Percentage Frequencies are obtained as follows:

Excellent = 18/50 * 100 = 36%

Very Good = 25/50 * 100 = 50%

Good = 4/50 * 100 = 8%

Fair = 1/50 * 100 = 2%

Poor = 2/50 * 100 = 4%

c) Good, very good, and excellent = 47/50 * 100 = 94%

d) Fair or Poor rating = 3/50 * 100 = 6%

 

e) Moreover, dissatisfied customers can be sources of great information on the performance of a good or service.  Though, with only 6% of customers giving a dissatisfaction rating with the Delta flights, it is still important to dive deep to unearth the reasons for their dissatisfaction as this may provide valuable information to improve the services.  Usually, this class of customers is the most sincere in most cases, unless their dissatisfaction can be proved to be attitudinal on their own part.

6 0
3 years ago
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