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anastassius [24]
3 years ago
12

The sculpture consists of five identical prisms. JD says the surface area of the sculpture is 44 times the surface area of one p

rism. Which statement about JD's method is true?

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
The complete question in the attached figure

we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy

now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy

we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.

the answer is 
</span>JD should also subtract the areas of eight hidden surfaces<span>

</span>

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When c=3 and d=7<br> 21c + 2d - |-11|d
NeX [460]

Answer:

0

Step-by-step explanation:

21(3) +2(7) - 11(7)             because the absolute value of -11 is 11

63+14-77

=0

8 0
3 years ago
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

= $6,240

Hence,

The correct answer is option (a) $6,240

7 0
3 years ago
What is the equation of the line graphed below?
vladimir2022 [97]

Answer:

it would A)y =-3x

Step-by-step explanation:

4 0
3 years ago
What is the multiplicative inverse of -1/3
motikmotik
-1/3 . -3/1 = 1
......................
4 0
3 years ago
I need help please it’s ASAP
malfutka [58]

The interquartile range of the data is equal to 2.18.

<h3>What is an interquartile range?</h3>

The interquartile range is a measure of where a data set's "middle fifty" is located. Whereas a range is a measure of where the start and end of a set are, an interquartile range is a measure of where the majority of the values are.

Given data is { 1.56,1.77,2.22,2.35,2.45,2.77,3.26,4.35,5.23,6.02}.

The upper limit is, and the median is 2.22.

{ 1.56,1.77,<u>2.22</u>,2.35,2.45,2.77}

The lower limit is, and the median is 4.35.

{2.77,3.26,<u>4.35</u>,5.23,6.02}

The interquartile range will be calculated as,

IQR = 4.35 - 2.22

IQR = 2.18

To know more about interquartile range follow

brainly.com/question/21270410

#SPJ1

5 0
10 months ago
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