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anastassius [24]
3 years ago
12

The sculpture consists of five identical prisms. JD says the surface area of the sculpture is 44 times the surface area of one p

rism. Which statement about JD's method is true?

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0
The complete question in the attached figure

we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy

now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy

we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.

the answer is 
</span>JD should also subtract the areas of eight hidden surfaces<span>

</span>

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miss Akunina [59]

Answer:

The probability that the intersection will come under the emergency program is 0.1587.

Step-by-step explanation:

Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.

Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.

For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.

Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).

W = \frac{X-\mu}{\sigma} = \frac{X-3}{1/2} = 2x-6

The values of \phi , the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program

P(X > 3.75) = P(2X-6 > 2*3.75-6) = P(W > 1) = 1-\phi(1) = 1-0.8413 \\= 0.1587

Download pdf
7 0
3 years ago
John is making himself a lunch. He has three different soups to choose from, four kinds of soda, and three different kinds of fr
Levart [38]
<span>3*4*3=36 so the answer is 36</span>
3 0
3 years ago
A school administrator believes that the mean class gpas for a given course are higher than the preferred mean of 2.75 at a sign
Svetach [21]

The mean GPA is greater than 2.75.

<h3>What is GPA?</h3>
  • A grade point average is a figure that represents the average of the final grades obtained in courses over time.
  • A student's grade point average, sometimes known as a GPA, is computed by adding all accumulated final grades and dividing the total by the number of grades granted.

To find the GPA:

  • GPA is calculated and could be utilized by the college to tell choices, which include the subsequent educational progression.
  • Divide the total range of grade factors earned with the aid of the total number of letter-graded units undertaken.
  • Mean GPA = total/50
  • = 2.75.

Therefore, the mean GPA is greater than 2.75.

Know more about GPA here:

brainly.com/question/17010398

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4 0
2 years ago
A librarian is putting 87 books in boxes for
emmainna [20.7K]

Answer:

there will be 8 boxes filled and 7 extras books

8 0
3 years ago
Read 2 more answers
Plzz help
Lina20 [59]

Answer:

$14

Step-by-step explanation:

40% of 10 is 4

4+10=14

hope this helps

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