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Goryan [66]
3 years ago
15

A baker uses 3/4 cup of honey in one of his cakes.There are 60 calories in 1/8 cup of honey.

Mathematics
2 answers:
Aleks [24]3 years ago
4 0
60 calories in 1/8 cup...how many calories in 3/4 cup
60 / (1/8) * 3/4

3/4 cups of honey for 1 cake, how many cups for 15 cakes
3/4 * 15

how many cakes could the baker make if he has 7/8 cup of honey
(7/8) / (3/4)


Westkost [7]3 years ago
3 0
1) 60/(1/8)*(3/4)
2)(3/4)*15
3)(7/8)/(3/4)
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Answer:

a. angles A and C

b. angles B and D

Step-by-step explanation:

When two lines are parallel, it implies the value of the angle between them is 180^{0}. Thus the lines can not meet when extended continuously.

Alternate angles are two equal angles that lie on opposite sides of the transversal line. Alternate Interior Angles are a pair of equal angles on the inner side of two parallel lines.

Since lines DE and AB are parallel with alternate interior angles at B and D, then angles A and C with angles B and D are alternate interior angles.

i.e         < A = < C (alternate interior angle property)

            <B = < D (alternate interior angle property)

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2 years ago
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step by step

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In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
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Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

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AC=\sqrt{\frac{193}{36} } = 2.315cm

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