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lozanna [386]
3 years ago
8

-5mn + 6n - 4m + 2mn + 8n + 3m simplify please show your work

Mathematics
2 answers:
BARSIC [14]3 years ago
7 0

Answer:

-3mn + 14n - m is your answer.

Step-by-step explanation:

Combine like terms (terms with the same amount of variables). Reorder so that it is so:

(-5mn + 2mn) + (6n + 8n) + (-4m + 3m)

Combine like terms. Add or subtract the variables. Note that if there is no number, it is assumed that there is a 1:

(-5mn + 2mn) = (2mn - 5mn) = -3mn

(6n + 8n) = 14n

(-4m + 3m) = 3m - 4m = -m

(-3mn) + (14n) + (-m)

-3mn + 14n - m is your answer.

~

wel3 years ago
7 0

Answer:

−3mn−m+14n

Step-by-step explanation:

(−5m)(n)+6n−4m+2mn+8n+3m

=−5mn+6n+−4m+2mn+8n+3m

Combine Like Terms:

=−5mn+6n+−4m+2mn+8n+3m

=(−5mn+2mn)+(−4m+3m)+(6n+8n)

=−3mn+−m+14n

Answer:

=−3mn−m+14n

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A variable contains five categories. It is expected that data are uniformly distributed across these five categories. To test th
lubasha [3.4K]

Answer:

33.293 ± 0.01= 33.303 and 33.383,

Step-by-step explanation:

We first need to fit a normal distribution , but neither the mean  nor the standard deviation is given . We therefore estimate the sample mean and sample standard deviation  <em>s</em>. Using the data we find ∑fx=<u>378 </u>  and

<u>∑fx²=1344   </u> so that mean x` = 2.885 or 2.9   and standard deviation s =1.360

x        f                fx       x²         fx²

1       27             27        1          27

2       30           60         4          120

3       29           87         9          261

4       21            84         16        336

<u>5       24           120       25        600           </u>

<u>      ∑f=131      ∑fx=378             ∑fx²=1344   </u>

Mean = x`=<u> </u> ∑fx/ <u>  </u>∑f=  2.9

Standard Deviation = s= √∑fx²/∑f-(∑fx/∑f)²

                  s= √1344/131 - (378/131)²

                   s= √10.26-(2.9)²

                     s= √10.26- 8.41

                    s= √1.85= 1.360

Next we need to compute the expected frequencies for all classes and the value of chi square. The necessary calculations for expected frequencies , ei`s ( ei= npi`) where pi` is the estimate of pi together with the value of chi square are shown below.

Categories      zi`      P(Z<z)             pi`       Expected         Observed

                                                                    frequency ei    Frequency Oi

1                     -1.39      0.0823    0.0823       10.78                  27

2                   -0.66       0.2546     0.1723         22.57                30

3                    0.07        0.5279      0.2733       35.80                 29

4                   0.808      0.7881       0.2602        34.08                21

5                    1.54        0.937          0.1489        19.51                 24

Next we need to compute the expected frequencies for all classes and the value of chi square. The necessary calculations for expected frequencies , ei`s ( ei= npi`) where pi` is the estimate of pi together with the value of chi square are shown below.

Categories           Expected         Observed       (oi-ei)²/ei

                       frequency ei    Frequency Oi         OBSERVED VALUE

1                            10.78                  27                     24.41

2                          22.57                30                         1.54

3                          35.80                 29                        1.29

4                         34.08                21                           5.02

5                          19.51                 24                         1.033

<u>Total                                              131                   33.293</u>

There are five categories , we have used the sample mean and sample standard deviation , so the number of degrees of freedom is 5-1-2= 2

The critical region is chi square ≥ chi square (0.001)(2) =9.21

<u>CONCLUSION:</u>

Since the calculated value of chi square =9.21  does not fall in the critical region we are unable to reject our null hypothesis and conclude normal distribution provides a good fit for the given frequency distribution.

7 0
4 years ago
Ce Powered by MathXL - Inv. 2 - Thinking With Mathematical ... Copy 4
MAVERICK [17]

Answer:

y=640-3x

Step-by-step explanation:

The total amount of ounces in the bucket is 640, and it decreases by 3 each minute. For example, if you plug in 3 for x into that equation (which would represent 3 minutes), you would lose 9 ounces of water, which makes sense in the terms of the equation.

7 0
3 years ago
An athletic director pays $90 for 12 sun visors for the softball team. a. How much will the athletic director pay to buy 15 more
Likurg_2 [28]
Get the unit rate.

90 / 12 = 7

$7.50 for a sun visor.

15 * 7.5 = 112.5

The athletic director needs to pay $112.5 to buy 15 more sun visors.
7 0
4 years ago
I need with this. Someone help please.
seraphim [82]

Answer:

In the ATTACHMENT

Step-by-step explanation:

For the first one, you can plug in multiple numbers of any kind for x and start to form you line.

For the second one, know that the y line is always horizontal. Find -3 on the plot that would be on the y-axis and put that horizontal line on it.

<em>Hope this helps!!</em>

4 0
4 years ago
Which is the best estimate of the number of times amber would pull out a new york quarter if she pulled out a quarter another 30
Anna [14]
I found the table that contains the following data:
25 times:
Column No.      1     2     3    4    5    Total

New York         3     2     2    1    2     10
Connecticut      1     1     1    2    0       5
Pennsylvania    1     1     1    1    1       5
Rhode Island    0     1     1    1     2       5

New York: 10/25 or 2/5
Connecticut: 5/25 or 1/5
Pennsylvania: 5/25 or 1/5
Rhode Island: 5/25 or 1/5

300 times * 2/5 = 120 times for New York

The best estimate of the number of times Amber would pull out a New York quarter is 120.
8 0
3 years ago
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