The mass of a dust particle is 0.000000000753 kg. How would this number be written in scientific notation?

What must be true about the discriminant of this quadratic equation for the mentioned values of k? Assume p>0.

Goryan [66]

1/(4p)(x-h)^2+k=0

1/(4p)(x-h)^2 = -k

k(4p)(x-h)^2+1=0

4kp (x^2 - 2xh + h^2) + 1 = 0

4kp x^2 - 8kph x + 4kph^2+1 = 0

D = (-8kph)^2 - 4(4kp)(4kph^2+1) = 64(kph)^2 - 64(kph)^2 - 16kp
D = -16kp < 0

SO discriminant is always less than 0

4 0

3 years ago

How to get a custom background on graphing calculator

Monica [59]

Answer:

scroll down to image :)! u can store 10 imgs. or u can change bg color! but thats for ti-84 ce!

Step-by-step explanation:

4 0

2 years ago

The weight of a product is normally distributed with a mean of four ounces and a variance of .25 squared ounces. What is the pro

ololo11 [35]

Answer:

$P(X>3.75)=P(\frac{X-\mu}{\sigma}>\frac{3.75-\mu}{\sigma})=P(Z>\frac{3.75-4}{0.5})=P(z>-0.5)$

And we can find this probability using the complement rule and we got:

$P(z>-0.5)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(4,\sqrt{0.25}=0.5)$

Where $\mu=4$ and $\sigma=0.5$

We are interested on this probability

$P(X>3.75)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>3.75)=P(\frac{X-\mu}{\sigma}>\frac{3.75-\mu}{\sigma})=P(Z>\frac{3.75-4}{0.5})=P(z>-0.5)$

And we can find this probability using the complement rule and we got:

$P(z>-0.5)=1-P(z$

5 0

3 years ago

1.What is the ratio of v to v max expressed as a percentage when [s] = 30 km

Helga [31]

Answer:

(a)96.77%

(b)3.23%

Step-by-step explanation:

Starting with the Michaelis-Menten equation which is used to model biochemical reactions:

Dividing both sides by $V_{\max }}$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}$

Where: $V_{\max }} =$ maximum rate achieved by the system

$K_{\mathrm {M} }}$ =The Michaelis constant

${\displaystyle {\ce {[S]}}}=$ Substrate concentration

(a) When $[S]=30K_M$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{30K_M}{K_M + 30K_M}\\\dfrac{v}{V_{max}}=\dfrac{30}{1 + 30}\\\dfrac{v}{V_{max}}=\dfrac{30}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{30}{31}X100=96.77\%$

(b)When $K_M=30[S]$

$\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{[S]}{30[S] + [S]}\\\\=\dfrac{1[S]}{30[S] + 1[S]}\\=\dfrac{1}{30 + 1}\\\dfrac{v}{V_{max}}=\dfrac{1}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{1}{31}X100=3.23\%$

8 0

3 years ago

Which decimal is equivalent to 26/9

grandymaker [24]

Answer:

The decimal 2.8 is equivalent to 26/9

Hope this helps

3 0

2 years ago