Answer:
127.7924
Step-by-step explanation:
Given that women’s weights are normally distributed with a mean given by µ = 143 lb and a standard deviation given by σ = 29 lb.
Let x be the weight of women
X is N (143, 29)
Or is N(0,1)
From standard normal distribution table we can find D3 i.e. 30th percentile and then convert suitably to X score
30th percentile in Normal =-0.5244
Corresponding X = Mean -0.5244 * std deviation
=
The third decile, D3, which separates the bottom 30% from the top 70%.___is 127.7924____