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NeTakaya
3 years ago
11

Do 1/3 and 2/6 name the same part of one whole?

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
Yes. 1/3 = 2/6.
To test, simplify 2/6 by dividing the numerator and denominator each by 2 (as 2/2 = 1) and you get 1/3.
You might be interested in
4. Which of the following describes all the solutions of -4x + 2y > 12 when y = 4?
Alja [10]

Answer:

Option B is correct

Step-by-step explanation:

Given data

We are given the expression

-4x + 2y > 12

We want to substitute y=4 into the expression

-4x + 2(4) > 12

-4x + 8 > 12

-4x> 12-8

-4x> 4

divide both sides by -4

x> 4/-4

x>-1

Hence option B is correct

5 0
3 years ago
What is the remainder when (2x3 + x2 – 3x + 4) is divided by x – 2?
sergeinik [125]

Answer:

The remainder is  

−

7

Step-by-step explanation:

When  

P ( x ) = 2 x 3 – x 2 – 3 x + 7  is divided by  x + 2 ,we are dividing by  x −( − 2), so the remainder will be: P ( − 2 ) = 2 − 2 ) 3 –

(

−

2

)

2

–

3

(

−

2

)

+

7

=

−

16

−

4

+

6

+

7

=

−

20

+

13

=

−

7

8 0
3 years ago
What's the answer ?????
ra1l [238]
1/2 because it's 2 times smaller
7 0
3 years ago
HelloI need some assistance with this question. I provided an answer, but it was incorrect. The images are enclosed.
ycow [4]

Given:

There are given that the zeroes and degrees of the polynomial:

\begin{gathered} \text{zeros:}-2,2,4 \\ \text{Degres:}3 \end{gathered}

Explanation:

From the concept of a polynomial:

A polynomial has a as zero if and only if (x -a) is a factor of the polynomial.

Then,

From the given polynomial:

f(x)=(x+2)(x-2)(x-4)

Then,

\begin{gathered} f(x)=(x+2)(x-2)(x-4) \\ f(x)=(x^2-2x+2x-4)(x-4) \\ f(x)=(x^2-4)(x-4) \\ f(x)=x^3-4x^2-4x+16 \end{gathered}

Final answer:

Hence, the polynomial is shown below:

f(x)=x^3-4x^2-4x+16

6 0
1 year ago
Use graph to answer question
slamgirl [31]

Answer:

cos(θ) = 3/5

Step-by-step explanation:

We can think of this situation as a triangle rectangle (you can see it in the image below).

Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.

Here we want to find cos(θ).

You should remember:

cos(θ) = (adjacent cathetus)/(hypotenuse)

We already know that the adjacent cathetus is equal to 3.

And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:

3^2 + 4^2 = H^2

We can solve this for H, to get:

H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5

The hypotenuse is 5 units long.

Then we have:

cos(θ) = (adjacent cathetus)/(hypotenuse)

cos(θ) = 3/5

5 0
3 years ago
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