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Usimov [2.4K]
1 year ago
7

Select all of the true comparisons.

Mathematics
2 answers:
sertanlavr [38]1 year ago
7 0

Answer: A, D, B

Step-by-step explanation:

Phoenix [80]1 year ago
5 0

Answer:A,B,D

yw :):):)

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Arithematic mean between 2-x and 2+x
alexgriva [62]

Answer:

2

Step-by-step explanation:

The mean is calculated as

mean = \frac{sum}{count} = \frac{2-x+2+x}{2} = \frac{4}{2} = 2

6 0
3 years ago
Discuss how the t-test for correlated groups and the t-test for single samples are alike and different.
SOVA2 [1]
In one sample t-test, you compare it to some value that you already know to represent the population mean. In the t-test for correlated groups, the statistic is the difference between your two samples, which you test against the population mean difference.
3 0
3 years ago
Can you help me with number 10
rewona [7]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{(3^{-2})^2}{3^{-3}}\implies \cfrac{3^{-2\cdot 2}}{3^{-3}}\implies \cfrac{3^{-4}}{3^{-3}}\implies \cfrac{1}{3^{-3}\cdot 3^4}\implies \cfrac{1}{3^{-3+4}}\implies \cfrac{1}{3^1}\implies \cfrac{1}{3}

4 0
4 years ago
Solve for X.<br> 4(2x + 5) + 2x + 3 = -11
S_A_V [24]
We can begin by rewriting the problem:

4(2x + 5) + 2x + 3 = -11

Let’s solve in steps.

1. Distribute

8x + 20 + 2x + 3 = -11

2. Combine like terms

10x + 23 = -11

3. Subtract 23 from both sides

10x + (23 - 23) = -11 - 23

10x = -34

4. Divide both sides by 10

10 / 10 = 1 (or x)

-34 / 10 = -3.4

Therefore, x = -3.4.
3 0
1 year ago
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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