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Mkey [24]
3 years ago
9

timmy writes the equation f(x) = x – 1. He then doubles both of the terms on the right side to create the equation g(x) = x – 2.

How does the graph of g(x) compare to the graph of f(x)?
Mathematics
1 answer:
EleoNora [17]3 years ago
3 0
<span>First, g(x) = 2x - 2, because when you double both of the terms of x - 1, you have to multiply each of the terms by two, i.e x * 2 = 2x and (-1) * 2 = - 2, so the result is 2x - 2. Comparing the graphs, you have that g(x) 's slope is 2, whils f(x) 's slope is 1, so that means that g(x) is more inclined or, what is the same, grows faster than f(x). Also, you can compare the y-intercepts, given that the y-intercept is the constant terms. So, the y-intercept of g(x) is -2, while the y-intercept of f(x) is - 1. </span>
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(0.6613, 8.3387)

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s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(15-1)(3.09)^{2}+(7-1)(2.58)^{2}}{15+7-2} = 8.68

The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{15}+\frac{1}{7}}, i.e.,

(69.4-64.9)\pm t_{0.005}2.946\sqrt{\frac{1}{15}+\frac{1}{7}}

where t_{0.005} is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So  

4.5\pm(-2.845)(2.946)(0.458), i.e.,

(0.6613, 8.3387)

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