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gizmo_the_mogwai [7]
2 years ago
13

Sadida needed to reorder shirts for her clothing store. She ordered 63 medium shirts and 27 large shirts. What was the ratio of

medium to large shirts.
Mathematics
1 answer:
Ber [7]2 years ago
8 0

Step-by-step explanation:

the ratio medium to large was

63/27 = 7/3

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sdas [7]

Answer:

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Step-by-step explanation:

8 0
3 years ago
If your starting salary were $40,000 and you received a 3% increase at the end of every year for 15 years, what would be the tot
Dmitry [639]

T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15


Multiply the above equation by 1.03 giving


1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16


Now subtract the first equation from the second to give


0.03T = 40000(1.03)^16 - 40000


0.03T = 40000(1.03^16 - 1)


0.03T = 24188.26


T = 24188.26 / 0.03 = $806275.25


6 0
3 years ago
Read 2 more answers
A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean
Dovator [93]

Answer:

B) 0.0069

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{9.1 - 8.4}{0.2846}

Z = 2.46

Z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0
3 years ago
If angle PQR equal 15 degrees in the triangle PQR, what is the value of u?
Anvisha [2.4K]

Answer:

a.

Step-by-step explanation:

7 0
2 years ago
A highway between points A and B has been closed for repairs. An alternative route between there two locations is to travel betw
Kitty [74]

Answer:

The value of Y is 24 km and distance from A to C to B is AC+Y=18+24=42 km

Step-by-step explanation:

Given that A highway between points A and B has been closed for repairs. An alternative route between there two locations is to travel between A and C and then from C to B. we have to find the value of Y and the total distance from A to C to B. Let AB=Z

In ΔBCD and ΔABD

∠BCD=∠ABD       (∵each 90°)

∠D=∠D                 (∵common)

By AA similarity, ΔBCD~ΔABD

∴ their corresponding sides are proportional

\frac{Y}{Z}=\frac{X}{40}=\frac{40}{18+X}

Comparing last two terms, we get

\frac{X}{40}=\frac{40}{18+x}

⇒ X(18+X)=1600

⇒ 18X+X^2=1600

⇒ X^2+18X-1600=0

⇒ X^2-32X+50X-1600=0

⇒ (X-32)(X+50)=0

Hence, the roots are X=32, -50

X=-50 not possible as distance can never negative.

Hence, X=32 km

By applying Pythagoras theorem in ΔBCD we get

BD^2=BC^2+CD^2

40^2=Y^2+32^2

⇒ Y^2=1600-1024=576

⇒ Y=\sqrt576=24km

Hence, the value of Y is 24 km and the distance from A to C to B is AC+Y=18+24=42 km




5 0
3 years ago
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