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gizmo_the_mogwai [7]

2 years ago

13

Sadida needed to reorder shirts for her clothing store. She ordered 63 medium shirts and 27 large shirts. What was the ratio of

medium to large shirts.

1 answer:

Ber [7]2 years ago

8 0

Step-by-step explanation:

the ratio medium to large was

63/27 = 7/3

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Alguém faz essa conta em fração pra mim e urgente

sdas [7]

Answer:

ghg

Step-by-step explanation:

8 0

3 years ago

If your starting salary were $40,000 and you received a 3% increase at the end of every year for 15 years, what would be the tot

Dmitry [639]

T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15

Multiply the above equation by 1.03 giving

1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16

Now subtract the first equation from the second to give

0.03T = 40000(1.03)^16 - 40000

0.03T = 40000(1.03^16 - 1)

0.03T = 24188.26

T = 24188.26 / 0.03 = $806275.25

6 0

3 years ago

Read 2 more answers

A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean

Dovator [93]

Answer:

B) 0.0069

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846$

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{9.1 - 8.4}{0.2846}$

$Z = 2.46$

$Z = 2.46$ has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0

3 years ago

If angle PQR equal 15 degrees in the triangle PQR, what is the value of u?

Anvisha [2.4K]

Answer:

a.

Step-by-step explanation:

7 0

2 years ago

A highway between points A and B has been closed for repairs. An alternative route between there two locations is to travel betw

Kitty [74]

Answer:

The value of Y is 24 km and distance from A to C to B is AC+Y=18+24=42 km

Step-by-step explanation:

Given that A highway between points A and B has been closed for repairs. An alternative route between there two locations is to travel between A and C and then from C to B. we have to find the value of Y and the total distance from A to C to B. Let AB=Z

In ΔBCD and ΔABD

∠BCD=∠ABD (∵each 90°)

∠D=∠D (∵common)

By AA similarity, ΔBCD~ΔABD

∴ their corresponding sides are proportional

$\frac{Y}{Z}=\frac{X}{40}=\frac{40}{18+X}$

Comparing last two terms, we get

$\frac{X}{40}=\frac{40}{18+x}$

⇒ $X(18+X)=1600$

⇒ $18X+X^2=1600$

⇒ $X^2+18X-1600=0$

⇒ $X^2-32X+50X-1600=0$

⇒ $(X-32)(X+50)=0$

Hence, the roots are X=32, -50

X=-50 not possible as distance can never negative.

Hence, X=32 km

By applying Pythagoras theorem in ΔBCD we get

$BD^2=BC^2+CD^2$

$40^2=Y^2+32^2$

⇒ $Y^2=1600-1024=576$

⇒ $Y=\sqrt576=24km$

Hence, the value of Y is 24 km and the distance from A to C to B is AC+Y=18+24=42 km

5 0

3 years ago