7.
(2b^2+7b^2+b)+(2b^2-4b-12)
(9b^2+b)+(2b^2-4b-12)
9b^2+b+2b^2-4b-12
11b^2+b-4b-12
11b^2-3b-12
8.
(7g^3+4g-1)+(2g^2-6g+2)
7g^3+4g-1+2g^2-6g+2
7g^3-2g-1+2g^2+2
7g^3-2g+1+2g^2
7g^3+2g^2-2g+1
Hope this helps!
Answer:
a = 6
Explanation:
7a − 17 = 4a + 1
Subtract 4a from both sides
7a − 17 − 4a = 4a + 1 − 4a
3a − 17 = 1
Add 17 to both sides
3a − 17 + 17 = 1 + 17
3a = 18
Divide both sides by 3
3a / 3 = 18 / 3
a = 6
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
Answer:
No
Step-by-step explanation:
x = -2 represents a vertical line that intersects the x axis at the point (-2, 0). Since the line is vertical, the slope is undefined making it not have a positive slope.
Best of Luck!
Answer:
-40
-6
51
Step-by-step explanation:
-33+-7 you are adding two negatives
9+(-15) you are adding a negative to a positive which gets you closer to zero
5-(-46) you are subtracting a negative which is adding
