Ask question

Ask question

All categories

4 years ago

6

What is the amount of oil for a sports car? 5 gallons, 5 quarts or 5 cups

1 answer:

kumpel [21]4 years ago

6 0

Answer:

Option A.

Step-by-step explanation:

We need to find the amount of oil for a sports car.

We know that,

1 quart = 4 cups

1 gallon = 4 quarts = 16 cups

Since, quart and cup are small units and they are not sufficient for a sports car because sports car needs more oil, therefore the amount of oil for a sports car is 5 gallons.

Therefore, the correct option is A.

You might be interested in

Find the measure of arc DB in P<br><br>please hurry if you can

jeyben [28]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: m \overbrace{DB} + m \overbrace{TB} = 180 \degree$

[ linear pair ]

$\qquad \tt \rightarrow \: m \overbrace{DB} + 90 \degree = 180 \degree$

$\qquad \tt \rightarrow \: m \overbrace{DB} = 180 \degree - 90 \degree$

$\qquad \tt \rightarrow \: m \overbrace{DB} = 90 \degree$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

2 years ago

Give an example of a piecewise function

Dominik [7]

Answer:

f(x) = 6 when -5 < x ≤ -1

Step-by-step explanation:

3 0

3 years ago

Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants

musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error for the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.22$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample should she take?

We need a sample size of at least n.

n is found when $M = 0.02$

So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}$

$\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}$

$n = 1160.88$

Rounding up

We need a sample size of at least 1161.

7 0

4 years ago

Solve by using substitution. Express your answer as an ordered pair.

Vanyuwa [196]

(7,4) hope that helps!

5 0

3 years ago

Find(x^2-3x+2)-(3x^2+5x+7).

Marina CMI [18]

Answer:

$- 2 {x}^{2} - 8x - 5$

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

#

3 0

3 years ago