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3 years ago

Simplify the expression. show work. 9xy^ - 11xy^

1 answer:

4 0

^ means to the power of with nothing after it, it's miss-used. Solving without the ^ symbol it is -2xy with the ^ symbol it's irrational and cannot be solved.

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Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 47.3 m

Marta_Voda [28]

Answer:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

Step-by-step explanation:

Assuming the following dataset:

Speed 42-45 46-49 50-53 54-57 58-61

Freq. 21 15 6 4 2

And we are interested in find the mean, since we have grouped data the formula for the mean is given by:

$\bar X = \frac{\sum_{i=1}^n x_i f_i}{\sum_{i=1}^n f_i}$

And is useful construct a table like this one:

Speed Freq Midpoint Freq*Midpoint

42-45 21 43.5 913.5

46-49 15 47.5 712.5

50-53 6 51.5 309

54-57 4 55.5 222

58-61 2 59.5 119

Total 48 2276

And the mean is given by:

$\bar X = \frac{2276}{48}=47.417$

If we compare this value with the 47.3 proposed we have the following error

$Error = \frac{|Actual-real|}{real}*100 = \frac{|47.417-47.3|}{47.3}*100 =0.247\%$

The computed mean is close to the actual mean because the difference between the means is less than 5%.

6 0

3 years ago

Simplify 4.510. a 4.51 b 1

attashe74 [19]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

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4vir4ik [10]

72 I think it is I believe

5 0

3 years ago

Perform the indicated operations. Write the answer in standard form, a+bi. 5-3i / -2-9i

Vsevolod [243]

$\huge \boxed{\mathfrak{Answer} \downarrow}$

$\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\$

Multiply both numerator and denominator of $\sf \frac{5-3i}{-2-9i} \\$ by the complex conjugate of the denominator, -2+9i.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)}) \\$

Multiplication can be transformed into difference of squares using the rule: $\sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$ .

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}}) \\$

By definition, i² is -1. Calculate the denominator.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85}) \\$

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

$\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85}) \\$

Do the multiplications in $\sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right)$ .

$\large \bf \: Re(\frac{-10+45i+6i+27}{85}) \\$

Combine the real and imaginary parts in -10+45i+6i+27.

$\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85}) \\$

Do the additions in $\sf-10+27+\left(45+6\right)i$ .

$\large \bf Re(\frac{17+51i}{85}) \\$

Divide 17+51i by 85 to get $\sf\frac{1}{5}+\frac{3}{5}i \\$ .

$\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i) \\$

The real part of $\sf \frac{1}{5}+\frac{3}{5}i \\$ is $\sf \frac{1}{5} \\$ .

$\large \boxed{\bf\frac{1}{5} = 0.2} \\$

3 0

3 years ago

Explain how you might use the properties of multiplication to solve 5 × 120 × 6.232 mentally. Then solve.

zysi [14]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In this question, we apply the associative property that calculates the given value, which can be defined as follows:

Rule:

$\bold{\to (A\times B)\times C= A \times (B\times C)}$

Let,

$A= 5\\B=120\\C=6.232$

put the value in the above rule:

Solve L.H.S part:

$\to (5\times 120)\times 6.232\\\\\to (600)\times 6.232\\\\\to 3,739.2$

Solve R.H.S part:

$\to 5 \times (120 \times 6.232)\\\\\to 5 \times 747.84\\\\\to 3,739.2$

So, L.H.S=R.H.S

6 0

3 years ago