Answer:
Since the null hypothesis is true, finding the significance is a type I error.
The probability of the year I error = level of significance = 0.05.
so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5
Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.
Her electricity bill will be of 14256 pence.
<em><u>Explanation</u></em>
On average, Tanya uses 90 units of electricity per week.
So, the <u>total units of electricity in 12 weeks</u> will be:
units
One unit of electricity costs 13.2 pence.
Thus, <u>the total cost for 1080 units</u> will be:
pence.
So, her electricity bill will be of 14256 pence.
Answer:
y=-2x+2
Step-by-step explanation:
okay?.......................
Answer:
q .no d
Step-by-step explanation:
64p^3+125
4p^3+ 5^3
(4p+ 5 ) ( 4p^2- 4p *5 + 5^2)
(4p+5) (16p- 20p+ 25)