Answer:
D is the answer
Step-by-step explanation:
Ok I’ll bet it will work for me and you
Let m be mean
Mean= sum/ n
Mean= (1720+1687+1367+1614+1460+1867+1436) / 7
m= 11151 / 7
M= 1593
Mean= 1593
Standard deviation
|x-m|^2
For 1st: |1720-1593|^2=8836
For 2nd: |1687-1593|^2=10201
For 3rd: |1367-1593|^2=51076
For 4th: |1614-1593|^2=441
For 5th: |1460-1593|^2=1689
For 6th: |1867-1593|^2=75076
For 7th: |1436-1593|^2=24649
Summation of |x-m|^2 = 171968
Standard deviation sample formula is:
S.D = sqrt((summation of |x-m|^2) / n-1)
S.D=sqrt(171968/6)
S.D=sqrt(28661.33)
S.D=169.30
Standard deviation is 169.30
There are four sides
6.5 x 4 = 26
Answer:
Step-by-step explanation:
<u><em>the mean in period</em></u> 1 :
(2.3+2.1+2.2+2.2+2.2+2.1+2.4+2.5+2.2+2.0+1.9+1.9+2.1+2.2+2.3)÷15=21.733...
<u><em>the mean in period</em></u> 2 :
(2.3+2.1+3.3+1.5+3.6+1.6+3.0+1.1+4.7+2.1+2.4+1.9+2.8+0.5+2.3)÷15=23.466...
Since 23.466 > 21.733 then “The mean in period 2 is higher than the mean in period 1”.
