The product of 5 and b

A sports store sells a 4 pack of tennis balls for $11.49, a 6 pack of tennis balls for $16.70, and a 9 pack for $22.99. Which pa

garik1379 [7]

Answer:

9 pack

Step-by-step explanation:

11.49/4=$2.87 per ball

16.70/6=$2.78 per ball

22.99/9=$2.55 per ball

4 0

3 years ago

Read 2 more answers

Identify the sequence as arithmetic, geometric, or neither. Explain your answer.

mestny [16]

This sequence (1.6, 0.8, 0.4, 0.2,... ) is geometric.
We have formula for any member of geometric sequence: $a_{n} = a_{1}* q^{n-1}$ If a1=1.6 then: $0.8=1.6*q, 0.4=1.6* q^{2}, 0.2=1.6* q^{3}$ The solution for all these equations is: q=0.5. We have: a1=1.6, q=0.5 and this is geometric sequence.

4 0

3 years ago

I WANT SOLUTION AND EXPLANATION ANSWER IS GIVEN AT LAST!!!

Serga [27]

let the numbers be x and y

x + y = 1600 ----*

12%x = 20%y

0.12x = 0.2y

y = 0.12x

0.2

y = 0.6x

substitute in * eqn

x + 0.6x = 1600

1.6x = 1600

x = 1000

then,

y = 0.6*1000

y = 600

the numbers are 1000 and 600

6 0

3 years ago

Read 2 more answers

In a triangle RSTV, RS=5.3cm and ST=4.1 find perimeter of RSTV

Luba_88 [7]

Is that a with 4 vertices ,,,check your question

7 0

3 years ago

A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the

EastWind [94]

Answer:

a) $\hat p=\frac{471}{1024}=0.460$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Data given and notation

n=1024 represent the random sample taken

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

$\hat p=\frac{471}{1024}=0.460$ estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.