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3 years ago

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How do I solve the problem you buy 3 t-shirts and 2 pairs of shorts for 42.50. Your friend buys 5 t-shirt and 3 pairs of shorts

for 67.50. Use a system of linear equations to find the cost of each t-shirt.

1 answer:

tensa zangetsu [6.8K]3 years ago

3 0

8 t-shirts and 5 pairs of shorts would be $110 all together each t-shirt would be i dont know

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Evaluate a+b for a=-17 and b=8

In-s [12.5K]

25

substitute 17 for A

substitute 8 for B

should look like this

17+8

then add

should look like this

17+8=25

8 0

3 years ago

Use the Distance Formula to find the distance to the nearest tenth between A(-7, -4) and B(-2, 0).

goldenfox [79]

A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41

the distance is approximately 6.4 units

8 0

3 years ago

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

Verdich [7]

Answer:

72 kg

Step-by-step explanation:

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

We are given the ratio

cement: sand:stones

= 1:2:4

The sum of proportion =

1 + 2 + 4 = 7

We are given the kg of sand = 144kg

Step 1

We find the total kg of cement, sand and stones = x

Using the proportion of sand,

2/7 of x = 144kg

2/7 × x = 144kg

2x/7 = 144kg

Cross Multiply

2x = 7 × 144kg

x = 7 × 144kg/2

x = 504kg

Therefore the total kg of cement, sand and stone = 504kg

Step 2

The amount of cement required is calculated as:

1/7 × 504 kg = 72 kg

Therefore, 72kg of cement is required.

4 0

3 years ago

Solve the equation by using the quadratic formula.<br> 3 x squared minus 1 = 7 x

Paladinen [302]

Answer:

b. $\frac{7+\sqrt{61} }{6} ,\frac{7-\sqrt{61} }{6}$

Step-by-step explanation:

$3x^{2} -1=7x$

Quadratic equations are suppose to be written as: $ax^2+bx+c=0$

so the new quadratic equation for this problem will be: $3x^{2} -1-7x=0$

Now rearrange the terms: $3x^{2} -7x-1=0$

Then use the Quadratic Formula to Solve for the Quadratic Equation

Quadratic Formula = $x=\frac{-b±}{} \frac{\sqrt{b^2-4ac} }{2a}$

Note: Ignore the A in the quadratic formula

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

$3x^{2} -7x-1=0$

a = 3

b = -7

c = -1

$x=-(-7)±\frac{\sqrt{(-7)^2-4(3)(-1)} }{2(3)}$

Evaluate The Exponent

$x=\frac{7±\sqrt{(49)-4(3)(-1)} }{2(3)}$

Multiply The Numbers

$x=\frac{7±\sqrt{49+12} }{2(3)}$

Add The Numbers

$x=\frac{7±\sqrt{61} }{2(3)}$

Multiply The Numbers

$x=\frac{7±\sqrt{61} }{6}$

4 0

3 years ago

The parabola x = y² - 9 opens: <br> a.)up <br> b.)down<br> c.) right <br> d.)left

Zolol [24]

Answer:

Right side towards positive x axis

Step-by-step explanation:

Let us see the basic rule to find the orientation of parabolas.

1. If power if x is 2 and y is 1 , the parabola opens up or down.

2. If the power of y is 2 and that of x is 1 , the parabola opens right or left.

3. If the coefficient of $x^{2}$ in case 1 is negative it opens downward

4. If the coefficient of $y^{2}$ in case 2 is negative , it opens left towards negative x axis.

Hence our equation is

$x=y^2-9$

here is satisfies the case 2. hence it opens right or left . Also the coefficient of

$y^{2}$ is positive so it opens up to the right side , that is towards positive x axis.

7 0

3 years ago