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vodomira [7]
3 years ago
12

How do I solve the problem you buy 3 t-shirts and 2 pairs of shorts for 42.50. Your friend buys 5 t-shirt and 3 pairs of shorts

for 67.50. Use a system of linear equations to find the cost of each t-shirt.
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0
8 t-shirts and 5 pairs of shorts would be $110 all together each t-shirt would be i dont know

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Evaluate the expression w^2 - v + 1 for w = -2 and v = -8.<br> -3<br> -11<br> 13<br> 5
seraphim [82]
-3
Because -2^2-8+1
-2to the second power is 4
4-8=-4
-4+1=-3
8 0
3 years ago
A Geiger counter counts the number of alpha particles from radioactive material. Over a long period of time, an average of 14 pa
UkoKoshka [18]

Answer:

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.

Each minute has 60 seconds, so \mu = \frac{14}{60} = 0.2333

Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.2333}*(0.2333)^{0}}{(0)!} = 0.7919

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7919 = 0.2081

0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.

8 0
3 years ago
If m∠2 = 41°, m∠5 = 94°, and m∠10 = 109°, find each measure.
Orlov [11]

Answer:

Step-by-step explanation:

It's given in this question,

m∠2 = 41°, m∠5 = 94° and m∠10 = 109°

Since, ∠2 ≅ ∠9 [Alternate interior angles]

m∠2 = m∠9 = 41°

m∠8 + m∠9 + m∠10 = 180° [Sum of angles at a point of a line]

m∠8 + 41 + 109 = 180

m∠8 = 180 - 150

m∠8 = 30°

Since, m∠2 + m∠7 + m∠8 = 180° [Sum of interior angles of a triangle]

41 + m∠7 + 30 = 180

m∠7 = 180 - 71

m∠7 = 109°

m∠6 + m∠7 = 180° [linear pair of angles]

m∠6 + 109 = 180

m∠6 = 180 - 109

        = 71°

Since m∠5 + m∠4 = 180° [linear pair of angles]

m∠4 + 94 = 180

m∠4 = 180 - 94

m∠4 = 86°

Since, m∠4 + m∠3 + m∠9 = 180° [Sum of interior angles of a triangle]

86 + m∠3 + 41 = 180

m∠3 = 180 - 127

m∠3 = 53°

m∠1 + m∠2 + m∠3 = 180° [Angles on a point of a line]

m∠1 + 41 + 53 = 180

m∠1 = 180 - 94

m∠1 = 86°

8 0
3 years ago
write the equation of a line in slope intercept form that passes through (2 -2) and is parallel to 2x+4y=8
Ne4ueva [31]

Answer:

y= -1/2x-1

Step-by-step explanation:

1) put the equation in y-intercept form to find the slope of the original line 2x+4y=8

y=8/4-2x/4

y=2-1/2x

slope of second line will be -1/2

2) put point into the point-slope form (2,-2)

y-(-2)= -1/2(x-2)  now simplify

y+2= -1/2x+2/2

y+2 = -1/2x + 1

y+2-2=-1/2x + 1 -2 ====>>>>  y= -1/2x-1

8 0
3 years ago
What is the equivalent exxpression of 8b+8-4b-3
sergiy2304 [10]
8b + 8 - 4b - 3

Combine like terms:-

(8-4)b + 8 - 3
4b + 8 - 3 
4b + 5 
4 0
3 years ago
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